Question

When 0.511 g of sodium metal is added to an excess of hydrochloric acid, 5310 J of heat are produced. What is the enthalpy of the reaction as written?

Answer 1

Answer:

The the enthalpy of the reaction is 241.36 KJ.

Explanation:

Given that,

Weight of sodium = 0.511 g

We need to calculate the number of moles

Using formula of moles

$moles=\dfrac{given\ mass}{molar\ mass}$

$moles=\dfrac{0.511}{23}$

$moles= 0.022$

We need to calculate the energy in 1 mole

In 0.022 moles of sodium metal = 5310 J

In 1 moles of sodium metal =$\dfrac{5310}{0.022}$

The Energy in 1 moles of sodium is 241363.63 J.

Hence, The the enthalpy of the reaction is 241.36 KJ.