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makvit [3.9K]
3 years ago
15

The buoyant force on a submerged boulder acts upward because _______.

Physics
1 answer:
vovikov84 [41]3 years ago
4 0
Greater water pressure acts on the bottom than on the top
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al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendri
3241004551 [841]

1) 12 cm

2) 3 N

Explanation:

1)

The relationship between force and elongation in a spring is given by Hooke's law:

F=kx

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

F=2 N

x=4 cm

So the spring constant is

k=\frac{F}{x}=\frac{2N}{4 cm}=0.5 N/cm

Later, the force is tripled, so the new force is

F'=3F=3(2)=6 N

Therefore, the new elongation is

x'=\frac{F'}{k}=\frac{6}{0.5}=12 cm

2)

In this second problem, we know that the elongation of the spring now is

x=6 cm

From part a), we know that the spring constant is

k=0.5 N/cm

Therefore, we can use the following equation to find the force:

F=kx

And substituting k and x, we find:

F=(0.5)(6)=3 N

So, the force to produce an elongation of 6 cm must be 3 N.

6 0
3 years ago
A student is trying to calculate the density of an ice cream cone. She already knows the mass, but she needs to determine the vo
vladimir2022 [97]
V= 1/3 π r²h 
this is the formula for a cone hope this helps :) 

5 0
3 years ago
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What one part of a circuit might cause your calculator to be off?
Tanzania [10]

Resistors tell me if im right

7 0
3 years ago
Which statement expresses the relationship between the frequency of emitted electrons and the energy they give off?
Nadusha1986 [10]
I think it would be the first choice
5 0
4 years ago
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. Starting from a stop at a traffic signal, a car speeds up to 20 m/s in 5 seconds. Calculate the acceleration of the car.
Dimas [21]

Answer: 4m/s²

Explanation:

At stop signal car speed iz 0 ; V1=0m/s

After t=5s  , car has speed is V2=20m/s

using:

a=(V2-V1)/t

a=(20m/s-0m/s)/5s

a=20m/s/5s

a=4m/s²

4 0
3 years ago
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