How do scientists assess changes in land cover and land use
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Answer:
C) 19 m/s
Explanation:
The motion of the cannonball is a projectile motion, which consists of 2 independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion (constant acceleration) along the vertical direction
As a result, we have the following:
- The horizontal velocity of the cannonball remains constant during the motion, and it is given by
where
u = 25 m/s is the initial velocity
is the angle
Substituting,
- The vertical velocity keeps changing during the motion due to the acceleration of gravity. However, at the top of the trajectory, the vertical velocity is zero:
This means that at the top of its path, the cannonball has only horizontal velocity, so its velocity is
C) 19 m/s
Answer:
31.831 Hz.
Explanation:
<u>Given:</u>
The vertical displacement of a wave is given in generalized form as
<em>where</em>,
- A = amplitude of the displacement of the wave.
- k = wave number of the wave =
= wavelength of the wave.
- x = horizontal displacement of the wave.
= angular frequency of the wave =
.
- f = frequency of the wave.
- t = time at which the displacement is calculated.
On comparing the generalized equation with the given equation of the displacement of the wave, we get,
therefore,
It is the required frequency of the wave.
Answer:
v₀ₓ = 28.6 m / s
Explanation:
This is a missile throwing exercise
y = t - ½ g t²
as the dart is thrown horizontally the vertical velocity is zero (I go = 0)
y = - ½ g t²
t =
let's calculate
t =
t = 0.175 s
the expression for horizontal displacement is
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 5.00 / 0.175
v₀ₓ = 28.6 m / s