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3 years ago

9.56 x 10^5 cg is how many grams?

Chemistry

1 answer:

Liula [17]3 years ago

4 0

Answer:

9.56×10¯⁷ g.

Explanation:

Mass in cg = 9.56×10¯⁵ cg

Mass in g =.?

Thus, we can convert 9.56×10¯⁵ cg to grams (g) as illustrated below:

Recall:

1 cg = 0.01 g

Therefore,

9.56×10¯⁵ cg = 9.56×10¯⁵ cg × 0.01 g / 1 cg

9.56×10¯⁵ cg = 9.56×10¯⁷ g

Therefore, 9.56×10¯⁵ cg is equivalent to 9.56×10¯⁷ g.

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The normal range of the pH of blood is between 7.35 and 7.45; variations beyond this range have significant health implications.

patriot [66]

Answer:

The hydrogen ion concentrations associated with these pH value 7.35 is $4.5\times 10^{-8} M$

The hydrogen ion concentrations associated with these pH value 7.45 is $3.6\times 10^{-8} M$ .

Explanation:

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

1) pH = 7.35

Putting values in above equation, we get:

$7.35=-\log[H^+]$

$[H^+]=4.467\times 10^{-8} M\approx 4.5\times 10^{-8} M$

The hydrogen ion concentrations associated with these pH value 7.35 is $4.5\times 10^{-8} M$

2) pH = 7.45

Putting values in above equation, we get:

$7.45=-\log[H^+]$

$[H^+]=3.548\times 10^{-8}M \approx 3.6\times 10^{-8} M$

The hydrogen ion concentrations associated with these pH value 7.45 is $3.6\times 10^{-8} M$ .

8 0

3 years ago

Hydrogen is manufactured on an industrial scale by this sequence of reactions:

hichkok12 [17]

Answer:

$K=K_1*K_2\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}$

Explanation:

Hello there!

In this case, for the given chemical reaction, it turns out firstly necessary to write the equilibrium expression for both reactions 1 and 2:

$K_1=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \\\\K_2=\frac{[CO_2][H_2]}{[CO][H_2O]}$

Now, when we combine them to get the overall expression, we infer these two are multiplied to get:

$K=K_1*K_2\\\\K=\frac{[CO][H_2]^3}{[CH_4][H_2O]} *\frac{[CO_2][H_2]}{[CO][H_2O]}\\\\K=\frac{[H_2]^3[CO_2][H_2]}{[CH_4][H_2O][H_2O]}$

Regards!

6 0

3 years ago

Plssss help————>An object thats (A. Negatively, B. Neutrally, C. Positively) charged has more electrons than protons. An obje

Inessa [10]

Answer:

1) negatively

2) positively

3) Neutral

Explanation:

6 0

3 years ago

Identify the element symbol 1s22s22p63s23p64s23d104p65s24d5

madam [21]

Answer:

Explanation:

You just have to follow the rows with the exponents. Just remember that when we get to d, the number in the front is a period lower. Hope this helps!

5 0

1 year ago

A sample of 9.27 g9.27 g of solid calcium hydroxide is added to 38.5 mL38.5 mL of 0.500 M0.500 M aqueous hydrochloric acid. Writ

navik [9.2K]

Answer: The excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For calcium hydroxide:

Given mass of calcium hydroxide = 9.27 g

Molar mass of calcium hydroxide = 74.093 g/mol

Putting values in above equation, we get:

$\text{Moles of calcium hydroxide}=\frac{9.27g}{74.093g/mol}=0.125mol$

To calculate the moles of a solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Volume of hydrochloric acid = 38.5mL = 0.0385 L (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.500 moles/ L

Putting values in above equation, we get:

$0.500mol/L=\frac{\text{Moles of hydrochloric acid}}{0.0385L}\\\\\text{Moles of hydrochloric acid}=0.01925mol$

For the given chemical equation:

$2HCl(aq.)+Ca(OH)_2(s)\rightarrow CaCl_2(s)+2H_2O(l)$

Here, the solid salt is calcium chloride.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium hydroxide.

So, 0.01925 moles of hydrochloric acid will react with = $\frac{1}{2}\times 0.01925=0.009625moles$ of calcium hydroxide.

As, given amount of calcium hydroxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (calcium hydroxide) left = 0.125 - 0.01925 = 0.115375 moles

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.01925 moles of hydrochloric acid will produce = $\frac{1}{2}\times 0.01925=0.009625moles$ of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 110.98 g/mol

Moles of calcium chloride = 0.009625 moles

Putting values in equation 1, we get:

$0.009625mol=\frac{\text{Mass of calcium chloride}}{110.98g/mol}\\\\\text{Mass of calcium chloride}=1.068g$

Hence, the excess reagent for the given chemical reaction is calcium hydroxide and the amount left after the completion of reaction is 0.115375 moles. The amount of calcium chloride formed in the reaction is 1.068 grams.

5 0

3 years ago

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