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m_a_m_a [10]
3 years ago
13

The sum of renting bowling shoes for $6 and $3 per game

Mathematics
2 answers:
Yakvenalex [24]3 years ago
3 0
3x +6b = x
b is the number of bowling shoes you rent
aliina [53]3 years ago
3 0

Answer:

9

Step-by-step explanation: 6+3=9

The rent is $9

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Gumballs cost $0.50 each, and jawbreakers cost $0.30 each. Bob has $3.00 to spend on candy.
KIM [24]

Answer:

0.5x+0.3y >= 3

sorry I don't know how to make the less than or equal to sign

Step-by-step explanation:

he can buy X amount of gumballs if he buys Y amount of jawbreakers and that will be less than or equal to $3

to graph, you must plug the number 0 into the X spot and solve.

0.5(0) +0.3y >= 3

next plug in for Y

0.5x+0.3(0) >= 3

plot these two points on the graph and draw a line through them

3 0
2 years ago
C<br> 10 mm<br> 24 mm<br> What is the length of the hypotenuse?
kompoz [17]

Answer:

26

Step-by-step explanation:

The Pythagorean Theorem states that a² + b² = c²

so, c = √(a² + b²)

10² + 24² = 676

√676 = 26

5 0
2 years ago
How wrote B plus 14 as a expression
Molodets [167]
All you need to do is put B+14=X
4 0
2 years ago
Read 2 more answers
In Sweden, 10 people are struck by lightning every year, on average. Answer thefollowing questions about a given year in Sweden
emmainna [20.7K]

Answer:

a) 19.85% probability that a total of two people are struck by lightning during first four months of the year.

b) 22.68% probability that the year has 5 good and 7 bad months

Step-by-step explanation:

We are going to use the Poisson distribution and the binomial distribition to solve this question.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a.Find the probability that a total of two people are struck by lightning during first four months of the year.

10 people during a year(12 months).

In 4 months, the mean is \mu = \frac{10*4}{12} = 3.33

This is P(X = 2).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-3.33}*(3.33)^{2}}{(2)!} = 0.1985

19.85% probability that a total of two people are struck by lightning during first four months of the year.

b.Say that a month is good is no one is struck by lightning, and bad otherwise. Find the probability that the year has 5 good and 7 bad months.

Probability that a month is good.

P(X = 0), Poisson

The mean is \mu = \frac{10*1}{12} = 0.8333

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.8333}*(0.8333)^{0}}{(0)!} = 0.4346

Find the probability that the year has 5 good and 7 bad months.

Now we use the binomial distribution, we want P(X = 5) when n = 12, p = 0.4346. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{12,5}.(0.4346)^{5}.(0.5654)^{7} = 0.2268

22.68% probability that the year has 5 good and 7 bad months

3 0
3 years ago
Please help I don't know what to do for number 40
valina [46]
X - tickets for adults
y - for students

6x+4.5y=1155\\&#10;x+y=240\\\\&#10;6x+4.5y=1155\\&#10;-4.5x-4.5y=-1080\\&#10;----------\\&#10;1.5x=75\\&#10;x=50\\\\&#10;50+y=240\\&#10;y=190
8 0
3 years ago
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