The blue mass in the image is 10kg.

A heavy rocket ship and a light rocket ship are both initially moving at 1000 kilometers per hour in outer space. They are very

cestrela7 [59]

Answer:Both will continue traveling at the same speed because there is no friction.

Explanation: Gravitational force or pull is the force acting to attract all object in and around the Earth to the center of the Earth. The Earth's Gravitational force acts as a Bar magnet.

When objects are working outside the impact of the force of Gravity,it will not matter whether the objects are of the same size or wether one is heavier than the other,in this case both objects will move at the same speed as there is no impact of the Force of Gravity.

8 0

4 years ago

(1 point) A projectile is fired from ground level with an initial speed of 600 m/sec and an angle of elevation of 30 degrees. Us

konstantin123 [22]

Answer:

(a) The range of the projectile is 31,813.18 m

(b) The maximum height of the projectile is 4,591.84 m

(c) The speed with which the projectile hits the ground is 670.82 m/s.

Explanation:

Given;

initial speed of the projectile, u = 600 m/s

angle of projection, θ = 30⁰

acceleration due to gravity, g = 9.8 m/s²

(a) The range of the projectile in meters;

$R = \frac{u^2sin \ 2\theta}{g} \\\\R = \frac{600^2 sin(2\times 30^0)}{9.8} \\\\R = \frac{600^2 sin (60^0)}{9.8} \\\\R = 31,813.18 \ m$

(b) The maximum height of the projectile in meters;

$H = \frac{u^2 sin^2\theta}{2g} \\\\H = \frac{600^2 (sin \ 30)^2}{2\times 9.8} \\\\H = \frac{600^2 (0.5)^2}{19.6} \\\\H = 4,591.84 \ m$

(c) The speed with which the projectile hits the ground is;

$v^2 = u^2 + 2gh\\\\v^2 = 600^2 + (2 \times 9.8)(4,591.84)\\\\v^2 = 360,000 + 90,000.064\\\\v = \sqrt{450,000.064} \\\\v = 670.82 \ m/s$

5 0

3 years ago

What is the bouncing of light when it changes media

matrenka [14]

When light passes from one medium to another, part of it continues on
into the new medium, while the rest of it bounces away from the boundary,
back into the first medium.

The part of the light that continues on into the new medium is transmitted
light. Its forward progress at any point in its journey is transmission.

Its direction usually changes as it crosses the boundary. The bending is 
refraction.

The part of the light that bounces away from the boundary and heads back
into the first medium is reflected light. The process of bouncing is reflection.

5 0

3 years ago

An object is placed exactly halfway between the Earth and moon. The object will fall toward the

Veronika [31]

Earth as the earth has a higher mass and therefore a higher gravitational force upon the object.

5 0

3 years ago

Read 2 more answers

At 13:20 on the last Friday in September, 1989 a frantic call was received at the local police station. There had been a serious

astraxan [27]

The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:

1) The principles of conservation of momentum and kinematics.

2) $\theta = tan^{-1} \frac{P_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.

To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.

When reviewing the kinematics relationships we have.

$v^2 = v_o^2 - 2 a x$

Where the acceleration is given by Newton's second law.

fr = m a

The friction force is given by the expression.

fr = μ N

fr = μ mg

Let's Substitute.

μ m g = m a

a = μ g

The friction coefficient is tabulated, for different types of rubber, pavement and wet, dry conditions, etc.

Therefore, the researcher must measure the braking distance of the vehicles, which can be taken from the mark of the tires on the road and note the condition of the pavement if it is dry or wet and the visibility of the day.

This is the speed of the vehicles just after the impact, using the law of conservation of momentum you can find the speed of the vehicles before the impact

$p_o = p_f$ \f

Where this is a vector expression, which in general is solved with the components of each directional.

Consequently to answer the questions you must use the principles of conservation of momentum and kinematics.

2) If the vehicles travel at right angles and their masses are similar, the direction after the collision in each direction.

$tan \theta = \frac{p_{01}}{p_{02}}$

$\theta = tan ^{-1} \frac{p_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

In conclusion, using the kinematics and conservation of momentum relationships, we can find the answers to the question about measurements and conditions to know the accident conditions are:

1) The principles of conservation of momentum and kinematics.

2) $\theta = tan^{-1} \frac{P_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

Learn more about kinematics and momentum here: brainly.com/question/17304001

5 0

3 years ago