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guajiro [1.7K]
3 years ago
9

Paco rode his skateboard up a ramp for a distance of 3.8 meters. If the ideal mechanical advantage of the ramp is 2, how far abo

ve the ground was Paco?
Physics
1 answer:
Hitman42 [59]3 years ago
8 0
The ideal mechanical advantage of an inclined plane or ramp  is equal to the length of incline divided by height of the inclined plane. in equation
MA = L / H
since the ideal mechanical advantage of the given inclined plane is 2 and the length of inlcine is 3.8 m

MA = L / H
H = L / MA
H = 3.8 / 2
H = 1.9 m was paco above the ground
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If you quadruple the temperature of a black body, by what factor will the total energy radiated per second per square meter incr
Anastaziya [24]
Radiant heat transfer is proportional to the 4-th power of absolute temperature.
Therefore if the temperature is quadrupled, the radiant heat energy will increase by a factor of
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8 0
3 years ago
A bird carrying a fish (5kg) drops it from 107 meters in the air how fast does the fish hit the ground
notka56 [123]

Answer:

The velocity of the fish hitting the ground is , v = 45.795 m/s        

Explanation:

Given data,

The mass of the fish, m = 5 kg

The height of the bird from the surface, h = 107 m

Using the III equation of motion,

                          v² = u² + 2gs

                          <em> v = √(u² + 2gs)</em>

Substituting the values,

                           v = √(0² + 2 x 9.8 x 107)  

                              = 45.795 m/s

Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s        

4 0
3 years ago
a uniform rod is hung at onen end and is partially submerged in water. If the density of the rod is 5/9 than of wter, find the f
34kurt

Answer:

    \frac{h_{liquid} }{ h_{body} } = 5/9

Explanation:

This is an exercise that we can solve using Archimedes' principle which states that the thrust is equal to the weight of the desalted liquid.

         B = ρ_liquid  g V_liquid

let's write the translational equilibrium condition

         B - W = 0

let's use the definition of density

        ρ_body = m / V_body

        m = ρ_body  V_body

        W = ρ_body  V_body  g

we substitute

          ρ_liquid  g  V_liquid = ρ_body  g  V_body

          \frac{\rho_{body}   }{\rho_{liquid} } } =  \frac{V_{liquid}   }{V_{body} } }

In the problem they indicate that the ratio of densities is 5/9, we write the volume of the bar

          V = A h_bogy

Thus

          \frac{V_{liquid} }{V_{1body} } = \frac{ h_{liquid} }{h_{body} }

we substitute

           5/9 = \frac{h_{liquid} }{ h_{body} }

8 0
2 years ago
A theory was not originally a hypothesis. true or false?
Serhud [2]
False.

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Answer:

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