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guajiro [1.7K]
4 years ago
9

Paco rode his skateboard up a ramp for a distance of 3.8 meters. If the ideal mechanical advantage of the ramp is 2, how far abo

ve the ground was Paco?
Physics
1 answer:
Hitman42 [59]4 years ago
8 0
The ideal mechanical advantage of an inclined plane or ramp  is equal to the length of incline divided by height of the inclined plane. in equation
MA = L / H
since the ideal mechanical advantage of the given inclined plane is 2 and the length of inlcine is 3.8 m

MA = L / H
H = L / MA
H = 3.8 / 2
H = 1.9 m was paco above the ground
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Answer:

  • |\vec{F}_3| = 102.92 \ N
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Explanation:

For an object to move with constant velocity, the acceleration of the object must be zero:

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So, the sum of the three forces must be zero:

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To obtain this sum, its easier to work in Cartesian representation.

First we need to define an Frame of reference. Lets put the x axis unit vector \hat{i} pointing east,  with the y axis unit vector \hat{j} pointing south, so the positive angle is south of east. For this, we got for the first force:

\vec{F}_1 = 83.7 \ N \ (-\hat{j}),

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Now, our third force will be:

\vec{F}_3  = - 83.7 \ N \ (-\hat{j}) - 59.9 \ N \ (-\hat{i})

\vec{F}_3  =  83.7 \ N \ \hat{j}  + 59.9 \ N \ \hat{i}

\vec{F}_3  =  (59.9 \ N , 83.7 \ N )

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To find the magnitude, we can use the Pythagorean theorem.

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

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|\vec{F}_3| = 102.92 \ N

this is the magnitude.

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\theta = arctan(\frac{F_{3_y}}{F_{3_x}})

\theta = arctan(\frac{83.7 \ N }{ 59.9 \ N })

\theta = 57 \° 24 ' 48''

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