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Sergio039 [100]
3 years ago
6

The temperature -273°C is —.

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

-273°C = Absolute zero

Explanation:

Average Kinetic energy of particles in matter refers to the temperature of matter. This value is not arbitrary zero temperature. It explains the lowest kinetic energy of the particles in matter.

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List the largest-aperture single telescope currently in use in each of the following bands of the electromagnetic spectrum: radi
tankabanditka [31]

Explanation:

Radio Telescope:

1. FAST (Five Hundred Meter Aperture Spherical Telescope), China is the largest single dish radio telescope in the world with a dish of diameter 500 meters. Although its construction is over but its not yet functional.

2. Arecibo Observatory, Puerto Rico is the largest single dish <em>operational</em> radio telescope having a single dish of diameter 305 meters..

X - ray Telescope: Chandra X ray observatory also known as Advanced X-ray Astrophysics Facility (AXAF) is the largest x-ray telescope with aperture of 1.2 meters. It can detect X-ray sources which are 100 times fainter in comparison to any previous telescope.

Gamma ray telescope: Fermi Gamma ray telescope is the largest gamma ray telescope.

4 0
3 years ago
A baseball is located at the surface of the earth. Which statements about it are correct? (There may be more than one correct ch
lakkis [162]

i think that the answer is a)

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3 years ago
Calculating heat gained or lost requires mass, specific heat, and
Anarel [89]
<span>Calculating heat gained or lost requires mass, specific heat, and

</span><span>c. change in temperature.</span><span>

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6 0
3 years ago
Why are vectors important in physics?
quester [9]
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7 0
3 years ago
A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x
SIZIF [17.4K]

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

4 0
2 years ago
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