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pychu [463]
3 years ago
14

Help!?!? Please and thank you

Physics
2 answers:
natita [175]3 years ago
3 0
C is probably the correct one
Grace [21]3 years ago
3 0
D. Almost all of earth is land and water The ice are from both north and south pole and the air covers all over earth.
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A mechanic needs to replace the motor for a merry-go-round. The merry-go-round should accelerate from rest to 1.5 rad/s in 7.0 s
marta [7]

Answer

given,

initial speed of merry-go-round = 0 rad/s

final speed of merry-go-round = 1.5 rad/s

time = 7 s

Radius of the disk = 6 m

Mass of the merry-go-round = 25000 Kg

Moment of inertia of the disk

I = \dfrac{1}{2}MR^2

I = \dfrac{1}{2}\times 25000\times 6^2

   I = 450000 kg.m²

angular acceleration

\alpha = \dfrac{\omega_f-\omega_0}{t}

\alpha = \dfrac{1.5-0}{7}

\alpha =0.214\ rad/s^2

we know,

\tau= I \alpha

\tau= 450000\times 0.214

\tau=96300\ N.m

8 0
3 years ago
Pam rubs a balloon on her head to generate a static charge. She holds the balloon up against a wall. Which of the following desc
cestrela7 [59]

Answer:

c

Explanation:

6 0
3 years ago
Which image shows the correct way of lining up vectors to add them
Marina CMI [18]

Answer:

it's A

Explanation:

wen aligning the vectors the head and the tail should meet

4 0
1 year ago
Which statement is true about a planet’s orbital motion?
lana66690 [7]

Answer:

Orbital motion results when the object’s forward motion is balanced by a second object’s gravitational pull.

Explanation:

The gravitational force is responsible for the orbital motion of the planet, satellite, artificial satellite, and other heavenly bodies in outer space.

When an object is applied with a velocity that is equal to the velocity of the orbit at that location, the body continues to move forward. And, this motion is balanced by the gravitational pull of the second object.

The orbiting body experience a centripetal force that is equal to the gravitational force of the second object towards the body.

The velocity of the orbit is given by the relation,

                                    V = \sqrt{\frac{GM}{R + h} }

Where

                   V - velocity of the orbit at a height h from the surface

                    R - Radius of the second object

                    G - Gravitational constant

                    h - height from the surface

The body will be in orbital motion when its kinetic motion is balanced by gravitational force.

                         1/2 mV^{2} = GMm/R

Hence, the orbital motion results when the object’s forward motion is balanced by a second object’s gravitational pull.

3 0
3 years ago
This object is located 13.0 cm to the left of the lens and the image forms at 20.8 cm to the right of the lens.
Alina [70]

Answer:

0.125 cm

Explanation:

1/f = 1/d¡ + 1/d。

Find the focal point

(13.0^-1 + 20.8^-1) = 0.125 m

Focal point = 0.125 m  

6 0
2 years ago
Read 2 more answers
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