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Ghella [55]
3 years ago
8

A lab cart with a mass of 15 kg is moving with constant

Physics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:c

Explanation: i guessed but got it right bc im a bad bleep lol

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A wind-tunnel experimentis performed on a 1/25scale model of a supersonic aircraft. The prototype aircraft flies at 450 m/s in c
KengaRu [80]

Answer: V = 504m/a

F = 4N

Explanation: please find the attached file for the solution

4 0
3 years ago
A airplane travels 3260 kilometers in 4 hours. What is the airplane average speed?
zavuch27 [327]
I'm pretty sure that it's 815.
4 0
3 years ago
Estimate the total number of bacteria and other prokaryotes in the biosphere of the earth. (assume the bacteria are found to a d
Fofino [41]
Since the Earth is almost spherical in shape, we are actually to find first the volume of the spherical segment at a depth of 1,000 m. The radius of the Earth is 6,371,000 meters. The volume of a spherical segment is:

V = 1/3*πh²(3r - h)
Substituting the values and making sure the units is in mm,
V = 1/3*π(1000 m * 1000 mm/1 m)²[3(6,371,000 m * 1000 mm/1 m) - (1000 m * 1000 mm/1 m)]
V = 2×10²² mm³

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7 0
4 years ago
Drosera magnifica is an organism that was first discovered in 2015.
mestny [16]

Answer:

The correct answer is - Plantae.

Explanation:

Drosera m<em>agnifica</em> is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

3 0
3 years ago
A 7300 N elevator is to be given an acceleration of 0.150g by connecting it to a cable of negligible weight wrapped around a tur
Firlakuza [10]

Answer:

α =18.75  rad/s²

Explanation:

Given that

Acceleration a = 0.15 g

We know that   g =10 m/s²

a= 0.15 x 10 = 1.5  m/s²

d= 16 cm

Radius r= 8 cm

Lets take angular acceleration =α rad/s²

As we know that

a= α r

Now by putting the values

1.5 = α  x 0.08

α =18.75  rad/s²

6 0
4 years ago
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