Given ON, what is measure of arc AC?*<br> оооо

I desperately need this question answered. See attached image thanks so much

Dahasolnce [82]

For this case we must follow the steps below:

step 1:

We place each of the given points on a coordinate axis

Step 2:

We join the AC points (represented by the orange line)

We join the BD points (represented by the blue line)

It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.

In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: $m1 * m2 = -1$

In this case, the slope of the orange line is $m1 = 1$ and that of the blue line is $m2 = -1$

Then $m1 * m2 = 1 * -1 = -1$ , it is verified that they are perpendicular.

Thus, the conclusion is that ABCD is a rhombus and AC is perpendicular to BD.

Answer:

See attached image

Option D

6 0

2 years ago

If you sleep 33% in a day, how many hours is that?

strojnjashka [21]

We know that
one day is equal to $24 hrs$
so
$33$ % of the day is equal to
$(\frac{33}{100} )*24 \\ =7.92 hrs$

the answer is
$7.92 hrs$

5 0

2 years ago

Read 2 more answers

A housepainter mixed 5 gal of blue paint with every 9 gal of yellow paint in order to make a

NikAS [45]

I think any of these would work

10;18

15;28

20;35

8 0

2 years ago

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A scientist running an experiment starts with 100 bacteria cells. These bacteria double their population every 15 hours. Find ho

IRISSAK [1]

<h2>Hello!</h2>

The answer is: 23.77 hours

$Total(t)=Start*2^\frac{t}{15}$

Where:

Total(t) is equal to the amount for a determined time (in hours)

<em>Start</em> is the original amount

<em>t </em>is the time in hours.

For example, it's known from the statement that the bacteria double their population every 15 hours, so it can be written like this:

$Total(15)=100*2^\frac{15}{15}=100*2^{1}=100*2=200$

To calculate how long it takes for the bacteria cells to increase to 300, we should do the following calculation:

$300=100*2^{\frac{t}{15} } } \\\frac{300}{100}=2^{\frac{t}{15} } }\\log(3)=log(2^{\frac{t}{15} })\\\\\\log(3)=\frac{t}{15}*log2\\t=\frac{log(3)}{log(2)} *15=23.77$