Given :
2 Mg + O₂ → 2 MgO
To Find :
How many moles of magnesium oxide are formed if you burn a 2.3 mol sample of magnesium ribbon in the air.
Solution :
From given balanced chemical reaction we can see that 2 mole of Magnesium reacts with 1 mole of O₂ to produce 2 mole of MgO.
Since, there is abundance of oxygen in air.
Therefore, 2.3 moles of magnesium will produced 2.3 moles of magnesium oxide.
Answer:
Because the gravitational force alters
Explanation:
1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.
2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.
3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.
4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.
I'm not writing random things to reach the 20 character requirement so I can tell you that Magnesium has the least amount of atoms.
<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol
</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
reactants products
products- reactants:</span><span>
(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
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