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sweet [91]
3 years ago
15

The bells are adding a new room to their house. The room will be a cube with volume 8000ft3. They are going to put in hardwood​

floors, and the contractor charges10 ​$ per square foot. How much will the hardwood floors​ cost? The hardwood floors will cost ​$
Mathematics
1 answer:
puteri [66]3 years ago
4 0

Given:

Volume of a cubed room = 8000 cubic ft

Cost of floor hardwood = $10 per square foot

To find:

The total cost of floor hardwood.

Solution:

Let the each side of cubed room be x ft.

Volume of a cube is cube of its side.

Volume of a cubed room is 8000 cubic ft. So,

x^3=8000

Taking cube root on both sides.

x=20

So, length of each of room is 20 ft.

Area of base = length × breadth

So, area of base of room is

20\times 20=400\text{ ft}^2

It means, 400 sq ft  hardwood is required for the floor.

Cost of floor hardwood is $10 per square foot. So, total cost of hardwood floor is

400\times 10=4000

The hardwood floors will cost ​$4000.

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Simplify x + (7+14x)​
Brilliant_brown [7]

Answer:

15x + 7

Step-by-step explanation:

x + (7 + 14x)

x + 7 + 14x

15x + 7

8 0
3 years ago
A recent broadcast of a television show had a 10 ​share, meaning that among 6000 monitored households with TV sets in​ use, 10​%
Kisachek [45]

Answer:

Null and alternative hypothesis

H_0: \pi \geq0.25\\\\H_1: \pi

Test statistic z=-26.82

P-value P=0

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

H_0: \pi \geq0.25\\\\H_1: \pi

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056

The test statistic is calculated as:

z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056}  =-26.82

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

3 0
3 years ago
I need help solving these please help...
Ber [7]
5) y = 2x + 7
6) y = \frac{5}{4}x - 5.5
5 0
3 years ago
1.2.71
egoroff_w [7]

Answer:

Step-by-step explanation:

Set up an equation, where x is the number of gallons of 60% antifreeze solution.

Represent the percentages of antifreeze with decimal values.

0.6x + 0.3(80) = 0.5(x + 80)

Simplify and solve for x:

0.6x + 24 = 0.5x + 40

0.1x = 16

x = 160

So, you have to mix 160 gallons of a 60% antifreeze solution

6 0
3 years ago
Lydia sells intricately shaped holiday soaps for $9 each. After each holiday, she marks the related soap down to $6.75. What per
mote1985 [20]

Need to find the amount of the discount first

(9 - 6.75)  = 2.25$

then find the %                                                            

(2.25/9) * 100 = 225/9 = 25%

             

7 0
3 years ago
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