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Ganezh [65]
3 years ago
15

jake drags a sled of mass 10 kg across the snow. the sled is attached to a rope that he pulls with a force of 30 n at an angle o

f 25°. if there is no friction, what is the normal force acting on the sled?

Physics
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

The normal force is 85,42 N

Explanation:

There is no friction force, therefore there is no relationship between the normal force and the friction.

We can find the normal force using a free body diagram and check the forces that are acting on the sled. The total forces are equal to 0 because there is no movement in the y-axis. The movement exists only on the x-axis.

OverLord2011 [107]3 years ago
6 0

Answer:

85.3 rounded

Explanation:

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a boat traveling at a speed of 1.63 m / s has a kinetic energy of 52000 J what is the mass of the boat
BARSIC [14]

Answer:

39,098‬ kg

Explanation:

KE = .5 * m * v^2

52000=.5m * 1.63^2

52000=.5m * 2.66

52000/2.66=.5m

19,549 = .5m

19549/.5 = m

m=39,098‬ kg

5 0
3 years ago
The evil team of Ms. Moonstruck and Mr. Luny intend to deflect the Moon from its orbit around Earth by pulling it with a force o
BabaBlast [244]

Answer:

92867kg

Explanation:

DATA:

mass of the moon 'm_1'= 7.36 x 10^2^2kg

mass of the mini black hole 'm_2'=?

universal gravitational constant= 6.67x10^-^1^1 Nm²/kg²

distance 'r'= 7.47×10^6 m

force 'F'= 8170N

Newton's Law of Universal Gravitation is given by:

F=G\frac{m_1m_2}{r^2}

m_2=\frac{(8170)(7.47*10^6)^2}{(6.67*10^-^1^1)(7.36*10^2^2)}

m_2=92867kg

8 0
3 years ago
A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th
Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

8 0
3 years ago
A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.1 m/s. The drag force is of the form bv2 What is the value of b?
meriva
At terminal velocity, drag force becomes equal to weight. Therefore:
weight = bv²
0.0023 x 9.81 = b x 9.1²
b = 2.72 x 10⁻⁴
7 0
3 years ago
Read 2 more answers
How long does it take an automobile traveling 72.5 km/h to become even with a car that is traveling in another lane at 54.5 km/h
Novosadov [1.4K]

Answer:

7.83

Explanation:

Just using the speed ,distance and time relation..Let time be T

Use this formula and find the distance covered by automobile .

Do same for car ..

and at last subtract the distance of automobile to car =141.

i.e (Distance of automobile -Dist.of car )=141

4 0
4 years ago
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