All categories

3 years ago

Explain the trend in atomic radius as you progress up column 17

1 answer:

3 0

As you progress up any column on the periodic table the atomic radius gets smaller. Fluorine is a very small atom because it has very few electrons and Iodine is a very large atomic radius because it has many electrons.

You might be interested in

A graduated cylinder (approximate as a regular cylinder) has a radius of 1.045 cm and a height of 30.48 cm. What is the volume o

Stels [109]

Answer: 104.5 cm^3

Explanation:

6 0

3 years ago

How do chemicals affect the environment?

oee [108]

I believe the answer is C

4 0

3 years ago

If a neutral atom has 24 electrons and 26 neutrons how many protons does it have?

Salsk061 [2.6K]

Answer:

Explanation:

The number of protons in the atom of the neutral element will also be 24.

Protons are the positively charged particles in an atom.

Electrons are the negatively charged particles

Neutrons do not carry any charges at all

Now, in a neutral atom, the charge is balanced and the number of protons and electrons are the same in the atom.

So, since we have been given that the atom has 24 electrons, the number of protons will be 24.

3 0

2 years ago

Hi! I need help with this question, if it is possible, please answer immediately.

Dennis_Churaev [7]

Answer:

Explanation:

The paper clip allows elictricity to pass, unlike the eraser or paper

6 0

3 years ago

How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol

SVEN [57.7K]

<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u /> $3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} )$ = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

3 0

2 years ago