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3 years ago

9

I NEED HELP PLEASE, THANKS! :)

2 answers:

makkiz [27]3 years ago

8 0

Answer:

They move outwards.

They don't intersect each other at any point.

They show the electric field.

Explanation:

nata0808 [166]3 years ago

8 0

Answer:

Please read the answer below

Explanation:

the nature of these lines refers to the fact that positive charges generate field lines that are directed out of the positive charges, and in turn are directed towards some negative charge present somewhere in the universe.

By consensus, the electric field lines leave the positive charges and enter the negative charges. That is the reason why in a scheme like the shown in the image, is considered implicitly the existence of a negative charge, in some place of the universe.

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The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on

alekssr [168]

Answer:

The change in temperature is $\Delta T = 1795 K$

Explanation:

From the question we are told that

The temperature coefficient is $\alpha = 4 * 10^{-3 }\ k^{-1 }$

The resistance of the filament is mathematically represented as

$R = R_o [1 + \alpha \Delta T]$

Where $R_o$ is the initial resistance

Making the change in temperature the subject of the formula

$\Delta T = \frac{1}{\alpha } [\frac{R}{R_o} - 1 ]$

Now from ohm law

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This implies that current varies inversely with current so

$\frac{R}{R_o} = \frac{I_o}{I}$

Substituting this we have

$\Delta T = \frac{1}{\alpha } [\frac{I_o}{I} - 1 ]$

From the question we are told that

$I = \frac{I_o}{8}$

Substituting this we have

$\Delta T = \frac{1}{\alpha } [\frac{I_o}{\frac{I_o}{8} } - 1 ]$

=> $\Delta T = \frac{1}{3.9 * 10^{-3}} (8 -1 )$

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lianna [129]

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Explanation:

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