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3 years ago

I NEED HELP PLEASE, THANKS! :)

Physics

2 answers:

makkiz [27]3 years ago

8 0

Answer:

They move outwards.

They don't intersect each other at any point.

They show the electric field.

Explanation:

nata0808 [166]3 years ago

8 0

Answer:

Please read the answer below

Explanation:

the nature of these lines refers to the fact that positive charges generate field lines that are directed out of the positive charges, and in turn are directed towards some negative charge present somewhere in the universe.

By consensus, the electric field lines leave the positive charges and enter the negative charges. That is the reason why in a scheme like the shown in the image, is considered implicitly the existence of a negative charge, in some place of the universe.

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What is 3,278,000 as scientific notation?

jonny [76]

3.278*10^6 I think. Sorry if it’s wrong.

4 0

2 years ago

A skateboarder with a mass of 45 kilograms is riding on a skateboard with a mass of 2.5 kilograms. What should be the velocity o

klasskru [66]

So momentum is just velocity times mass, this means Momentum = Velocity x Mass.
We can rearrange this to be Velocity = Momentum/Mass.

Since we know momentum and mass we can now solve.

Velocity = 264/(45+2.5)
= 5.56 m/s

5 0

2 years ago

Read 2 more answers

Two electric charges A and B were placed facing each other at a distance of separation "r". The common electrostatic force betwe

lutik1710 [3]

Answer:

From the formula of force:

$F = \frac{kAB}{ {r}^{2} } \\$

since AB and k are constants:

$F \: \alpha \: \frac{1}{ {r}^{2} } \\ \\ F = \frac{x}{ {r}^{2} }$

x is a constant of proportionality

• when force is 4N, separation distance is 1

$4 = \frac{x}{1} \\ x = 4$

therefore, equation becomes

$F = \frac{4}{ {r}^{2} } \\$

when r is doubled, r becomes 2. find F:

$F = \frac{4}{ {2}^{2} } \\ \\ F = \frac{4}{4} \\ \\ { \underline{force \: is \: 1N}}$

5 0

3 years ago

Can someone help me?

Gwar [14]

24- series
25- parallel
26- no, because they’re connected in series
27- yes, because they’re connected in parallel

7 0

2 years ago

A circular parallel plate capacitor is constructed with a radius of 0.52 mm, a plate separation of 0.013 mm, and filled with an

olya-2409 [2.1K]

Answer:

289282

Explanation:

r = Radius of plate = 0.52 mm

d = Plate separation = 0.013 mm

A = Area = $\pi r^2$

V = Potential applied = 2 mV

k = Dielectric constant = 40

$\epsilon_0$ = Electric constant = $8.854\times 10^{-12}\ \text{F/m}$

Capacitance is given by

$C=\dfrac{k\epsilon_0A}{d}$

Charge is given by

$Q=CV\\\Rightarrow Q=\dfrac{k\epsilon_0AV}{d}\\\Rightarrow Q=\dfrac{40\times 8.854\times 10^{-12}\times\pi \times (0.52\times 10^{-3})^2\times 2\times 10^{-3}}{0.013\times 10^{-3}}\\\Rightarrow Q=4.6285\times 10^{-14}\ \text{C}$

Number of electron is given by

$n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{4.6285\times 10^{-14}}{1.6\times10^{-19}}\\\Rightarrow n=289281.25\ \text{electrons}$

The number of charge carriers that will accumulate on this capacitor is approximately 289282.

6 0

2 years ago