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yarga [219]
3 years ago
10

A desk was moved 12 m using 280 j of work. how much force was used to move the desk?

Physics
1 answer:
Oksana_A [137]3 years ago
4 0
Let F =  required force, N

Given:
d = 12 m, distance
W = 280 J, work done

By definition,
W = F*d,
therefore
(F N)*(12 m) = (280 J)
F = 280/12 = 23.33 N

Answer: The force is 23.3 N (nearest tenth)
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Answer:

\boxed{\sf Tension \ in \ the \ string \ (T) = 3 \ kN}

Given:

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To Find:

Tension in the string (T)

Explanation:

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\boxed{ \bold{ T = F_c  =  \frac{m {v}^{2} }{r} }}

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\sf \implies T =  \frac{3 \times  {20}^{2} }{0.4}  \\  \\  \sf \implies T = \frac{3 \times 400}{0.4}  \\  \\  \sf \implies T =3 \times 1000 \\  \\  \sf \implies T =3000 \: N \\  \\ \sf \implies T =3 \: kN

\therefore

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