There's no info about the cars starting off differently, so as far as we know they have been side by side all the way.
<span>So from the last telephone pole: </span>
<span>(a) and (b): the displacement of both cars is 65.5m
the average speed for both car is 65.5m/5.0s = 13.1m/s</span>
Answer:
d = 2*0.87 = 1.75 cm
Explanation:
by using flow rate equation to determine the speed in larger pipe



= 591.10 cm/s
= 5.91 m/s
by Bernoulli's EQUATION


solving for v2
v2 = 10.53 m/s
diameter can be determine by using flow rate equation



r = 0.87 cm
d = 2*0.87 = 1.75 cm
Explanation:
Efficiency = work out / work in
e = 571 J / 1694 J
e = 0.337
Answer:

Explanation:
The work of force 2 will be given by the vectorial equation
. We know the value of
and have information about its movement, which relates to the net force
.
About this movement we can obtain the acceleration using the equation
. Since it departs from rest we have
.
And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have 
And we had the work done by force 2 as:

(The sign will be given algebraically since we take positive the direction to the right.)
With our values:

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>
<em>
</em>
<em>Which leads us to the previous equation straightforwardly.</em>