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3 years ago

11)A 1100 kg car travels on a straight highway with a speed of 30 m/s. The driver sees a red light ahead and applies her

Physics

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

Time taken = 8.25 second

Explanation:

Given:

Force = 4000 N

Force = ma

4,000 = (1100)(a)

Acceleration = 3.6363 m/s²

v = u + at

0 = 30 + (3.6363)t

Time taken = 8.25 second

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What is the equivalent resistance of a circuit that contains two 50.0 32

Alex Ar [27]

82ohms

Explanation:

The equivalent resistance in the circuit is 82ohms

Given parameters:

R1 = 50ohms

R2 = 32ohms

Unknown:

Equivalent resistance = ?

Solution:

A resistor is an body in circuit that opposes the flow of electric current.

Resistors are usually connected in circuit and in series arrangement.

When resistors are connected in series, they have the same current passing through them.

Equivalent resistance is the sum of each of the connected resistors

Equivalent resistance = R1 + R2 = 50 + 32 = 82ohms

learn more:

Circuits brainly.com/question/2364338

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3 years ago

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A ball of mass 0.50 kg is fired with velocity 160 m/s into the barrel of a spring gun of mass 1.8 kg initially at rest on a fric

shepuryov [24]

Answer:

All fraction of kinectic energy is lost to barrel of a spring gun of mass 1.8 kg

Explanation:

A ball of mass 0.50 kg is fired with velocity 160 m/s ...

The kinetic energy is given by 1/2mv²

Kinectic energy of the ball = 1/2 *0.5*160²

Kinectic energy = 1/4 *25600

Kinectic energy = 6400 joules.

If no energy is lost to fiction, and the ball sticks to a barrel of a spring gun of mass 1.8 kg with initial velocity zero, all kinetic energy is lost to the barrel of a spring gun of mass 1.8 kg.

5 0

3 years ago

A water main pipe of diameter 10 cm enters a house 2 m below ground. A smaller diameter pipe carries water to a faucet 5 m above

Lemur [1.5K]

Explanation:

Given that,

Diameter = 10 cm

Distance = 2 m

Speed $v_{1}= 2\ m/s$

Speed $v_{2}=7\ m/s$

Pressure in main pipe $P_{1}=2\times10^{5}\ Pa$

(I). We need to calculate the diameter

Using equation of continuity

$Av_{1}=Av_{2}$

$\pi(\dfrac{d_{1}}{2})^2\times v_{1}=\pi(\dfrac{d_{2}}{2})^2\times v_{2}$

$(\dfrac{10}{2})^2\times2=(\dfrac{d_{2}}{2})^2\times7$

$d_{2}=\sqrt{\dfrac{25\times2\times4}{7}}$

$d_{2}=5.345\ cm$

(II). We need to calculate the pressure the gauge pressure

Using Bernoulli equation

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}$

$P_{2}=P_{1}+\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)-\rho g(h_{1}-h_{2})$

$P_{2}=2\times10^{5}+\dfrac{1}{2}\times1000(4-49)-1000\times 9.8\times(5)$

$P_{2}=1.28500\times10^{5}\ Pa$

(III). If it is possible to carry water to a faucet 17 m above ground,

Using Bernoulli equation

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh=P_{3}+\dfrac{1}{2}\rho v_{3}^2+\rho g h_{3}$

$P_{3}=P_{1}+\dfrac{1}{2}\rho v_{1}^2-\rho g(h_{1}-h_{3})$

Here, $h_{3}=0$

Put the value in the equation

$P_{3}=2\times10^{5}+\dfrac{1}{2}\times1000\times4-1000\times 9.8\times17$

$P_{3}=3.5400\times10^{5}\ Pa$

Hence, This is required solution.

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3 years ago

How can a charged object cause charges to move within an uncharged object?

Paraphin [41]

Thank you for posting your question here at brainly. Feel free to ask more questions.
The best and most correct answer among the choices provided by the question is A. If the uncharged object is a conductor, the charged object can attract opposite charges. 

Hope my answer would be a great help for you.

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3 years ago

Energy of a wave is measured in terms of the wave's ?

Tamiku [17]

Energy refers to the speed.So u use the formula speed=wavelength×frequency

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3 years ago

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