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iren [92.7K]
3 years ago
10

Over a period of one year, how much of the overall (night) sky would a Bellingham observer be able to see?

Physics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

The overall sky a Bellingham observer would see is about 75-100% over the period of 1 year.

Explanation:

Due to following factors, the overall sky visibility will fall in this range.

  1. The location of Bellingham on Earth is in the Northern hemisphere over the equator.
  2. The tilt of the earth cannot allow the visibility of the complete sky.
  3. The light pollution and aerosol concentrations has reduced the sky visibility at night.
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An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 34.5
Inessa05 [86]

Answer:

the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Explanation:

Given;

initial velocity of the airplane. u = 34.5 m/s

distance traveled by the airplane, s = 46,100 m

final velocity of the airplane, v = 40.7 m/s

The acceleration of the airplane is calculated from the following kinematic equation;

v² = u² + 2as

2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²

5 0
3 years ago
A burning piece of wood converts ____ energy into ____ energy​
liq [111]

Answer:

a burning piece of converts Chemical energy into Heat(Thermal) and Light energy

8 0
3 years ago
Find the correct statement
boyakko [2]

Answer:The disturbance created by a source of sound in the medium travels through the medium and not the particles of the medium

Explanation:i hope this is right

4 0
3 years ago
A copper wire of length L and cross-sectional area A has resistance R. A second copper wire at the same temperature has a length
qwelly [4]

Answer: 4R

Explanation:R=pL/A

R second wire=p2L/1/2A

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8 0
3 years ago
AP Physics I, shouldn't be too hard.
Nana76 [90]

Answer:

The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

The initial velocity of object X = v₀

The mass of object Y = 2·m₀

The initial velocity of object Y = -2·v₀

By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision =  9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

5 0
3 years ago
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