All categories

3 years ago

Over a period of one year, how much of the overall (night) sky would a Bellingham observer be able to see?

Physics

1 answer:

nika2105 [10]3 years ago

6 0

Answer:

The overall sky a Bellingham observer would see is about 75-100% over the period of 1 year.

Explanation:

Due to following factors, the overall sky visibility will fall in this range.

The location of Bellingham on Earth is in the Northern hemisphere over the equator.
The tilt of the earth cannot allow the visibility of the complete sky.
The light pollution and aerosol concentrations has reduced the sky visibility at night.

You might be interested in

A stone is launched from the ground, at a 70° angle, with an initial velocity of 120 m/s.

zavuch27 [327]

<span>A) x = 41t
The classic equation for distance is velocity multiplied by time. And unfortunately, all of your available options have the form of that equation. In fact, the only difference between any of the equations is what looks to be velocity. And in order to solve the problem initially, you need to divide the velocity vector into a vertical velocity vector and a horizontal velocity vector. And the horizontal velocity vector is simply the cosine of the angle multiplied by the total velocity. So H = 120*cos(70) = 120*0.34202 = 41.04242 So the horizontal velocity is about 41 m/s. Looking at the available options, only "A" even comes close.</span>

3 0

2 years ago

Read 2 more answers

What changes occurred when Zoroastrianism became a state religion during the Sasanian Empire?

statuscvo [17]

Zoroastrianism affected the way the Persians governed their subjects by allowing the territories under their rule to worship their own religion.

8 0

3 years ago

On a touchdown attempt, 95.00 kg running back runs toward the end zone at 3.750 m/s. A 113.0 kg line-backer moving at 5.380 m/s

dsp73

Answer:

(a) 1.21 m/s

(b) 2303.33 J, 152.27 J

Explanation:

m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s

(a) Let their velocity after striking is v.

By use of conservation of momentum

Momentum before collision = momentum after collision

m1 x u1 + m2 x u2 = (m1 + m2) x v

- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v

v = ( - 356.25 + 607.94) / 208 = 1.21 m /s

(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2

= 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)

= 0.5 (1335.94 + 3270.7) = 2303.33 J

Kinetic energy after collision = 1/2 (m1 + m2) v^2

= 0.5 (95 + 113) x 1.21 x 1.21 = 152.27 J

4 0

2 years ago

A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th

melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore, the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F = 624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

5 0

3 years ago

Volcanologists and seismologist are specialzed in what

antiseptic1488 [7]

The answer is:

They are specialized in geology and geophysics

1) Volcanologists are scientific researchers who study the properties of volcanoes and develop the science of predicting volcanic eruptions accurately.

- Volcanoes are the results of fissures in the earth's crust, from which magma, gases, rocks, and ashes can erupt.

-Volcanic eruptions and their impact on the atmosphere are investigated by specialist geologists known as volcanologists.

A) Volcanologists are scientists who use a variety of sophisticated equipment to measure and analyze volcanic activity, lava, rock, ashes and gases as well as earthquakes caused by eruptions.

B) Also, they measure the magnitude and intensity of explosions, placing them on a scale from 1 to 8 [volcanic explosivity index].

C)Volcanologists monitor both active and dormant volcanoes to try to predict eruptions and minimize adverse effects on people and their environment.

D)Also, they spend a lot of time collecting and analyzing samples of debris, rocks and other products from extinct volcanoes to gain a better understanding of the processes behind the volcanic activity and the impact former eruptions had in shaping the climate.

2) Seismologists are Earth scientists, specialized in geophysics, who study the genesis and the propagation of seismic waves in geological materials.

-Their research aims at interpreting the geological composition and structures of the Earth. In the case of earthquakes, seismologists evaluate the potential dangers and seek to minimize their impact through the improvement of construction standards.

5 0

3 years ago

Read 2 more answers