Catching a wave, a 77 kg surfer starts with a speed of 1.3 m/s, drops through a height of 1.65 m, and ends with a speed of 8.2 m
1 answer:
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Answer:
F' = 64 F
Explanation:
The electric force between charges is given by :
Where
q₁ and q₂ are charges
r is the distance between charges
When each charge is doubled and the distance between them is 1/4 its original magnitude such that,
q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)
New force,
Apply new values,
So, the new force becomes 64 times the initial force.
≈40.8kg
this is to take up space
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
