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Goshia [24]
3 years ago
12

I need help writing a Christmas story about electricity

Chemistry
1 answer:
dezoksy [38]3 years ago
3 0

Are you saying Santa invensted electricty...my childhood was a lie!!!!

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olchik [2.2K]
It should have 10 electrons
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I'm in a rush please help
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16) <

17) >

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4 years ago
What radionuclides is used in diagnosis of atherosclerosis
aliina [53]
Answer: technetium-99.

Explanation:

This is not an answer that you can look for in a book.

You need to do some research.

You can fiind the abstract of the article titled <span>Molecular imaging of atherosclerosis using a technetium-99m-labeled endothelin derivative.</span>

The conclusion of this scientific article is that labeling with the radiosotope Tc - 99 iis feasibele to visualize the effects of an experiment inducing atherosclerosis, which gives the answer to the question posted.
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4 years ago
90 POINTSSSS!!!
Katarina [22]

Answer:

\large \boxed{\text{-2043.96 kJ/mol}}

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn:    C₃H₈(g) +   O₂(g) ⟶   CO₂(g) +   H₂O(g)

Balanced eqn:    C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}

(b)Total enthalpies of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\=  \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}

ΔᵣH° is negative, so the reaction is exothermic.

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3 years ago
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Anuta_ua [19.1K]
Hydrogen Bond is the bond based on intermolecular forces between H and F O and N
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