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4 years ago

How many grams of CaC2 would make 23.6g C2H2 ?

Chemistry

1 answer:

Andrej [43]4 years ago

5 0

CaC2 + 2 H2O = C2H2 + Ca(OH)2

moles CaC2 = 485 g/64.1 g/mol=7.57

moles H2O = 2 x 7.57 =15.1

mass H2O = 15.1 mol x 18.02 g/mol=272.8 g

moles C2H2 = 23.6 /26.038 g/mol=0.906

moles CaC2 = 0.906

mass CaC2 = 0.906 x 64.1 =58.1 g

moles Ca(OH)2 = 55.3 / 74.092 =0.760

moles H2O = 2 x 0.760 =1.52

mass water = 18.02 x 1.52 =27.4 g

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3 years ago

How many km are in 5.6mm? 5.6x103 5.6x10-6 5.6x10-3 5.6x106

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Question: How many km are in 5.6mm?

=>5.6x10^3

=>5.6x10^-6

=>5.6x10^-3

=> 5.6x10^6

Answer:-

$5.6 \times 10^{ - 6}$

Explanation:-

By using the formula-

$1millimeter = \frac{1}{1000000}$

As 1 with 6 zeros, we convert it into exponential form.

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Now combine with given question.

$= > 5.6 \times 10^{ - 6}$

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2 years ago

You find a clean 100-ml beaker, label it "#1", and place it on a tared electronic balance. You add small amount of unknown solid

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Answer:

the mas is .291 g

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3 years ago

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The standard values of cell potentials are:

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Now we have to calculate the standard cell potential for the following reaction.

$E^0=E^0_{cathode}-E^0_{anode}$

$E^0=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cr^{3+}/Cr]}$

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Therefore, the standard cell potential of the reaction is, -1.46 V

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4 years ago

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4 years ago