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GenaCL600 [577]
3 years ago
13

What is the number of moles of H2O produced if you combust two moles of CH4 according to the following balanced equation? CH4 +

2 O2 --> CO2 + 2 H2O
Chemistry
1 answer:
loris [4]3 years ago
5 0
The combustion of Methane produces CO₂ and water;

                         CH₄  +  2 O₂     →      CO₂  +   2 H₂O

According to balance equation,

        1 Mole of CH₄ on combustion give  =  2 Moles of H₂O
So,
                  2 Moles of CH₄ will produce  =  X Moles of H₂O

Solving for X,
                               X  =  (2 Moles × 2 Moles) ÷ 1 Mole

                               X  =  4 Moles
Result:
           4 Moles 
of H₂O is produced on combustion of 2 Moles of CH₄.
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What state of matter is glass? Why does this seem odd?
melamori03 [73]

Answer:

solid

Explanation:

It is called an amorphous solid because it lacks the ordered molecular structure of true solids, and yet its irregular structure is too rigid for it to qualify as a liquid.

8 0
3 years ago
Read 2 more answers
Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina
yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

(AgNO3) + FeI(3) = AgI(3) + FeNO3

So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M

8 0
3 years ago
How many moles are in 4.5 g of<br> Sodium Chloride, NaCl?
Sergeu [11.5K]

Answer:

The answer to the question is 0.07 moles

6 0
2 years ago
The image shows two spheres hung from a thin rope. The spheres do not affect each other.
jekas [21]

Answer:

both spheres have a positive charge

8 0
3 years ago
Acetic acid has a Kb of 2.93 °C/m and a normal boiling point of 118.1 °C. What would be the boiling point of a solution made by
alexdok [17]

Boiling point elevation is given as:

ΔTb=iKbm

Where,

ΔTb=elevation in the boiling point

that is given by expression:

ΔTb=Tb (solution) - Tb (pure solvent)

Here Tb (pure solvent)=118.1 °C

i for CaCO3= 2

Kb=2.93 °C/m

m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)

=(100.0÷100 g/mol)/0.4

= 2.5 m

So now putting value of m, i and Kb in the boiling point elevation equation we get:

ΔTb=iKbm

=2×2.93×2.5

=14.65 °C

boiling point of a solution can be calculated:

ΔTb=Tb (solution) - Tb (pure solvent)

14.65=Tb (solution)-118.1

Tb (solution)=118.1+14.65

=132.75

3 0
3 years ago
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