(infinity -1/2]u [-1/2 -1/2] u [1/2 infinity)
It would be 7 on the side and then 2/6
6/8 because 3/4*2=6/8
hope this helps
∠ADC = 112°
∠ADC =6x + 7 + 12x - 3
Equate both:
6x + 7 + 12x - 3 = 112
Solve for x :
6x + 7 + 12x - 3 = 112
Combine like terms:
18x + 4= 112
Take away 4 from both sides:
18x = 108
Divide both sides by 18:
x = 6
Find ∠ADB:
6x + 7 = 6(6) + 7 = 43
Answer: ∠ADB = 43°
The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
#SPJ1
