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tankabanditka [31]
3 years ago
14

In the human body hydrochloric acid is responsible for the low ph of the contents of the

Chemistry
1 answer:
natulia [17]3 years ago
4 0
The wording makes this question difficult, but HCl is found in stomach acid. Hope this helps!
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Which notation is used to represent a beta particle?
Lapatulllka [165]
The beta particle is represented by the Greek letter <span>β. The beta particle is one of the particles that are emitted during radioactive decay. Beta particles are emitted in the process of beta decay. A beta particle can be in form of an electron or a positron. </span><span />
7 0
3 years ago
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A carbon atom has six electrons. How are these electrons shared in its atomic orbital shells?
umka21 [38]
The correct response is A. The inner she'll contains 2 electrons and the outer shell contains 4 electrons.
6 0
3 years ago
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Which is not needed for a hurricane to form?
aliya0001 [1]

Answer:

strong cold front

Explanation:

5 0
3 years ago
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A single hydrogen atom has a mass of 1.67 × 10−24 g. A sodium atom has an atomic mass of 23. How many sodium atoms are required
statuscvo [17]
<h3>Answer:</h3>

                      2.55 × 10²² Na Atoms

<h3>Solution:</h3>

Data Given:

                 M.Mass of Na  =   23 g.mol⁻¹

                 Mass of Na  =  973 mg  =  0.973 g

                 # of Na Atoms  =  ??

Step 1: Calculate Moles of Na as:

               Moles  =  Mass ÷ M.Mass

               Moles  =  0.973 g ÷ 23 g.mol⁻¹

               Moles  =  0.0423 mol

Step 2: Calculate No, of Na Atoms as:

As 1 mole of sodium atoms counts 6.022 × 10²³ and equals exactly to the mass of 23 g. So, we can write,

               Moles  =  No. of Na Atoms ÷ 6.022 × 10²³ Na Atoms.mol⁻¹

Solving for No. of Na Atoms,

               No. of Na Atoms  =   Moles × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =   0.0423 mol × 6.022 × 10²³ Na Atoms.mol⁻¹

               No. of Na Atoms  =  2.55 × 10²² Na Atoms

<h3>Conclusion: </h3>

                          2.55 × 10²² sodium atoms are required to reach a total mass of 973 mg in a substance of pure sodium.


5 0
3 years ago
How much heat in joules is gained when a 34.5 g bar of gold is heated from 26.4°C to 75.3°C ?specific heat of gold on 0.129 J/gr
Sati [7]

Answer:

Q = 217.63J

Explanation:

Data;

Mass = 34.5g

T1 = 26.4°C

T2 = 75.3°C

c = 0.129J/g°C

Energy (Q) = mc(T2 - T1)

Q = 34.5 * 0.129 *(75.3 - 26.4)

Q = 4.4505 * 48.9

Q = 217.629J

Q = 217.63J

The heat gained was 217.63J

7 0
3 years ago
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