Ask question

Ask question

All categories

3 years ago

13

A radio technician measures the frequency of an AM radio transmitter. The frequency is 11979kHz. What is the frequency in megahe

rtz? Write your answer as a decimal.

1 answer:

Murljashka [212]3 years ago

7 0

Answer:

11.979 MHz

Explanation:

$f = \text{11979 kHz} \times \dfrac{\text{1 MHz}}{\text{1000 kHz}} = \textbf{11.979 MHz}$

You might be interested in

If the solubility of KCl in 100 mL of H₂O is 34 g at 20 °C and 43 g at 50 °C, label each of the following solutions as unsaturat

sertanlavr [38]

Answer:

a) Unsaturated

b) Supersaturated

c) Unsaturated

Explanation:

A saturated solution contains the <u>maximum amount of a solute that will dissolve in a given solvent at a specific temperature</u>.

An unsaturated solution contains <u>less solute than it has the capacity to dissolve. </u>

A supersaturated solution, <u>contains more solute than is present in a saturated solution</u>. Supersaturated solutions are not very stable. In time, some of the solute will come out of a supersaturated solution as crystals.

According to these definitions and considering that the solubility of KCl in 100 mL of H₂O at <u>20 °C is 34 g</u>, and at <u>50 °C is 43 g</u> we can label the solutions:

a) 30 g in 100 mL of H₂O at 20 °C ⇒ unsaturated

b) 65 g in 100 mL of H₂O at 50 °C ⇒ supersaturated

c) 42 g in 100 mL of H₂O at 50 °C and slowly cooling to 20 °C to give a clear solution <u>with no precipitate</u> ⇒ unsaturated (if it were saturated it would have had precipitate)

8 0

3 years ago

Which statement describes heterogeneous mixtures?

Artemon [7]

<span>The righ answer is the option A. They are made up of two or more pure substances that are not chemically bonded. A classicall expample ot heterogeneous mixtures are sugar and salt. Sugar is a pure substance, salt is also a pure substance, when you mixe them you form mixture where salt is still salt and sugar is still sugar, that is what "they are not chemically bonded" means. So you can separate them by physical media. </span>

4 0

3 years ago

Read 2 more answers

If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te

attashe74 [19]

Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
$pV=nRT$
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
$\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}$

If the supported load is W kg, then
$p_{1} = \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} = 20.3718W \, Pa$
Similarly,
$p_{2} = \frac{4W}{\pi d_{2}^{2}} \, Pa$

$\frac{p_{1}}{p_{2}} = \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}$

Because p₁/p₂ = T₁/T₂, therefore
$16d_{2}^{2} = \frac{293}{423} \\\\ d_{2}^{2} = \frac{0.6927}{16} \\\\ d_{2} = 0.2081 \, m$

The minimum piston diameter at 150 C is 20.8 cm.

Answer: 20.8 cm diameter

8 0

3 years ago

Seaweed attached to rocks in the ocean performs photosynthesis underwater. Which statement best explains how some seaweed can su

tia_tia [17]

Answer:

It can use a small amount of sunlight for photosynthesis

Explanation:

Seaweeds are a group of marine plants/algae that grow attached to rocks underwater. However, despite their depth underwater, they still perform photosynthesis, which is a process that requires energy from sunlight.

Seaweeds are able to perform photosynthesis underwater because they are efficient users of sunlight energy. Hence, they require only a small amount of sunlight that penetrates the ocean to perform photosynthesis.

8 0

3 years ago

Convert the condensed structures to line angle formulas: 1. CH3CH2CH(CH3)CH2CH3 8. CH:COCH 9. CH3CH2OCH3 2. CH3CH2CH(CH2CH3)CH(C

kumpel [21]

Answer:

Attached in the photo.

Explanation:

Hello,

The answers in the attached photo. Just three things:

- In the second point a parenthesis is missing to properly understand the molecule (after the oxygen), nevertheless, I assumed it was an ether.

- In the sixth point, there's a missing hydrogen for it to be an ether as well.

- In the tenth point the second parenthesis is not clear, it seems there's a missing subscript, nevertheless I draw it assuming complete octates.

Best regards.

3 0

3 years ago