The balanced equation for the above reaction is as follows C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g) the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction. the amount of </span>C₆H₁₂O₆ used up - 13.2 g the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol stoichiometry of glucose to CO₂ - 1:6 then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol As mentioned this reaction takes place at standard temperature and pressure conditions, At STP 1 mol of any gas occupies 22.4 L Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L Answer is B) 10.0 L CO₂
