Question

How many liters of 

Answer 1

The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.  
the amount of C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol  = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions, 
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol  x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂