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myrzilka [38]
3 years ago
7

The following three functions look very similar, but define very different functions. Think about how they are defined and write

each as a composition of functions given the information below. (None of the functions in your compositions should be the same as the given function.) 1. sin^4 (x) = f(g(x)) where f(x) = , and g(x) = . 2. sin(sin(x)) = f(g(x)) where f(x) = , and g(x) = . 3. sin x^4 = f(g(x)) where f (x) = , and g(x) = .
Mathematics
1 answer:
tatiyna3 years ago
8 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following functions :

sin^4 (x) = f(g(x)) where f(x) = and g(x) =

Sin⁴(x) = sin(x)⁴

g(x) = sin(x),

f(x) = f(g(x)) = f(sin(x)⁴) = x⁴

2.) sin(sin(x)) = f(g(x)) where f(x) = , and g(x) =

g(x) = sin(x) ; sinx = x

g(x) = sin(x)

f(x) = f(g(x)) = sin(x) ; sin(x) = x

f(x) = f(g(x)) = f(sin(x))

f(x) = sin(x)

3. sin x^4 = f(g(x)) where f (x) = , and g(x) = .

Here,

g(x) = x⁴

f(x) = f(g(x)) = sin(g(x)) = sin x

f(x) = sinx

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> diameter = 2* radius = 0.31847 mile

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3 years ago
1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

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To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

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