Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.f(x)=(3x-4)(-6x+5)

1 answer:

4 0

At first glance, it might be tempting to say this is a linear function, because we see linear terms (3x and –6x); however, these are multiplied together, so it's actually a quadratic.

We need to expand the function (hint: use FOIL) to identify the terms.

$f(x)=(3x-4)(-6x+5)=-18x^2+39x-20$

The x^2-term, or quadratic term, is $-18x^2$ . The x-term, or linear term, is $39x$ . The number term, or constant term, is –20.

You might be interested in

While rolling, a wheel with a diameter of 19/2 ft makes 133 revolutions. Find the distance that is traveled by the wheel. Use 22

mojhsa [17]

You just need to find the circumference (the outside of the wheel) and then multiply that by how many times it turned

circumference is d* pi so your diameter 19/2 times pi (22/7) is about 29.86 ft
times that by 133 and you get exactly 3971 feet

3 0

3 years ago

Why is the petrol price cheaper at coastal than inland

Daniel [21]

Answer: If a litre of fuel at the coast (95 octane) costs R13,89, then 38% is tax. The difference between inland and coastal fuel prices is mainly due to transport costs of the fuel from depots at the coat to inland outlets.

5 0

3 years ago

Read 2 more answers

How can we factorise the expression: 2x^6+17x^3+8?

LekaFEV [45]

Answer:

$(a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1)$

Step-by-step explanation:

$2x^6+17x^3+8 \\ = 2x^6+16x^3 + {x}^{3} +8 \\ = 2{x}^{3} ( {x}^{3} + 8) + 1( {x}^{3} + 8) \\ = ( {x}^{3} + 8)(2 {x}^{ 3} + 1) \\ = ( {x}^{3} + {2}^{3} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + {2}^{2} )(2 {x}^{ 3} + 1) \\ = (a + 2)( {a}^{2} - 2a + 4 )(2 {x}^{ 3} + 1) \\$