Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms.f(x)=(3x-4)(-6x+5)
1 answer:
At first glance, it might be tempting to say this is a linear function, because we see linear terms (3x and –6x); however, these are multiplied together, so it's actually a quadratic.
We need to expand the function (hint: use FOIL) to identify the terms.
The x^2-term, or quadratic term, is
. The x-term, or linear term, is 
. The number term, or constant term, is –20.
We need to expand the function (hint: use FOIL) to identify the terms.
The x^2-term, or quadratic term, is
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The sum of angles in any quadrilateral, including trapezoid, is 360⁰.
Because we have <span>an isosceles trapezoid, we have 2 angles with measure 135⁰,
and we have 2 equal acute angles with measure x⁰.
So, we can find value of acute angle,
135*2 +2x =360⁰
270+2x=360
2x=360-270
2x=90
x=45⁰
So, acute angles in trapezoid = 45⁰.
From triangle ABC,
angle ACB =90⁰
angle A=45⁰,
so angle ABC= 180-(90-45)=45⁰
Triangle ABC is isosceles triangle,so |AC| = |CB|= 5 in.
So, longer base AA' = 5+4+5= 14 in
Now, we can find area of trapezoid.
shorter base = 4 in
longer base = 14 in
altitude =h = 5 in
Area of trapezoid =(1/2)(base1+base2)*h
Area of trapezoid = (1/2)(4+14)*5= 9*5=45 in²
Answer is 45 in².</span>
Because we have <span>an isosceles trapezoid, we have 2 angles with measure 135⁰,
and we have 2 equal acute angles with measure x⁰.
So, we can find value of acute angle,
135*2 +2x =360⁰
270+2x=360
2x=360-270
2x=90
x=45⁰
So, acute angles in trapezoid = 45⁰.
From triangle ABC,
angle ACB =90⁰
angle A=45⁰,
so angle ABC= 180-(90-45)=45⁰
Triangle ABC is isosceles triangle,so |AC| = |CB|= 5 in.
So, longer base AA' = 5+4+5= 14 in
Now, we can find area of trapezoid.
shorter base = 4 in
longer base = 14 in
altitude =h = 5 in
Area of trapezoid =(1/2)(base1+base2)*h
Area of trapezoid = (1/2)(4+14)*5= 9*5=45 in²
Answer is 45 in².</span>
Answer:
All of them are yes because you either subtract or add to put in the form of mx+b
