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GenaCL600 [577]
4 years ago
15

Why is it helpful to study the light that comes off stars?

Physics
1 answer:
asambeis [7]4 years ago
6 0
 It is helpful to study the light that comes off stars because C. The light from a star gives hints of what elements make up a star.
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An object moving with a constant
jeka57 [31]

Answer:

Acceleration:

{ \tt{a =  \frac{v - u}{t} }} \\ { \tt{a =  \frac{20 - 10}{5} }} \\ { \tt{a = 2 \: m {s}^{ - 2} }}

From third equation:

{ \bf{ {v}^{2}  =  {u}^{2}  + 2as}} \\ { \tt{s =  \frac{ {20}^{2}  -  {10}^{2} }{2 \times 2} }} \\   = { \tt{s = 75 \: m}}

5 0
3 years ago
Read 2 more answers
THE LARGEST HORIZONTAL PLATES IS SEPARATED BY 4mm .The plate is at the potencial of -6V . What potencial should be applied to th
Serhud [2]

Answer:

V₂ = -22 V

Explanation:

Electric potential and field are related

         ΔV = - E d

where ΔV is the potential difference between the plates, E the electric field and d the separation between the plates

 

In this exercise we are given the parcionero d = 4 mm = 0.004 m, the potential of one of the plates V1 = -6V and the value of the electric field E = 4000 V / m

          V₂- V₁ = - E d

          V₂ = - Ed + V₁

          V₂ = - 4000 0.004 + (- 6)

          V₂ = -16 - 6

          V₂ = -22 V

6 0
3 years ago
a crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one
prohojiy [21]

The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be 37^oC is 367.42 Hz.

A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.

The fundamental frequency in the tube is given by

f=\frac{v_T}{4L}

where, v_T=v\sqrt{\frac{T}{273} }

Since, T=37+273 K = 310 K

v = 331 m/s

\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s

Using this, we get:

f=\frac{352.72}{4(0.240)} \\f=367.42 \ Hz

Hence, the fundamental frequency is 367.42 Hz.

To learn more about Attention here:

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7 0
1 year ago
A woman falls to the ground while wearing a parachute. The air resistance on the parachute of the parachute is 500N. If the woma
scoundrel [369]

The gravitational force on the woman is A) 500 N

Explanation:

There are two forces acting on the woman during her fall:

  • The force of gravity, F_G, acting downward
  • The air resistance, F_D, acting upward

According to Newton's second law, the net force acting on the woman is equal to the product between the woman's mass and her acceleration:

\sum F=ma

where m is the mass of the woman and a her acceleration.

The net force can be written as

\sum F = F_G - F_D

Also, we know that the woman falls at a constant velocity (5 m/s), this means that her acceleration is zero:

a=0

Combining the equations together, we get:

F_G-F_D = 0

which means that the magnitude of the gravitational force is equal to the magnitude of the air resistance:

F_G=F_D=500 N

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5 0
3 years ago
Read 2 more answers
When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq
Lilit [14]

Answer:60 gm

Explanation:

Given

initial velocity of ball u=0

Force exerted by racquet F=540 N

time period of force t=5\ ms

final velocity of ball v=45\ m/s

Racquet imparts an impulse to the ball which is given by

J=F\Delta t=\Delta P

J=540\times \Delta t=m(45-0)

m=\frac{540\times 5\times 10^{-3}}{45}

m=60\ gm

8 0
3 years ago
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