Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Answer:
Step-by-step explanation:
Check attachment for better understanding of the data given
Since the given data is a linear data,
Then we can use equation of a line to find the relationship between x and y
Let pick any tel point from the given data
P1 = (x1, y1) = (1, 80)
P2 = (x2, y2) = (2, 160)
Then, equation of alone given two points can be determine using
∆y/∆x = y-y1 / x-x1
y2 - y1 / x2 - x1 = y-y1 / x-x1
160 - 80 / 2 - 1 = y - 80 / x - 1
80 / 1 = y - 80 / x - 1
Cross multiply
80(x - 1) = 1(y - 80)
80x - 80 = y - 80
Add 80 to both sides
80x - 80 + 80 = y - 80 + 80
80x = y
Then,
y = 80x
Then, the mistake useful made is multiplying x by 8 instead of multiply it by 80
So, the correct option is
D. Yosef should have multiplied the x-values by 80 to get the y-values.
Answer:
3.0 GPA
Step-by-step explanation:
A = 4.0
B = 3.0
C = 2.0
18 (all of the GPA's added up) / 6 (number of numbers) = 3.0
The odd numbers from one to six are 1,3.5 which is 3/6, when simplified it is one half. Can you mark branliest?
Answer:
hhughjHIBJYBJ8PPJJO00PKSOS