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Hitman42 [59]
3 years ago
15

Determine the number of atoms in the following chemical formulas. Make sure you list the elements, how many atoms of each elemen

t, and how many total atoms. Numbers 1 and 6 have been completed as examples.
8NaCl = 8+8=16 (To find the total number of atoms add the total number of atoms)
Na=1x8=8 (remember to multiply the subscript by the coefficient)
Cl=1x8=8

H₂SO₄ = _______
H=
S=
O=

4KNO₃ = _______
K=
N=
O=

CaCl₂ = _______
Ca=
Cl=

3C₂H₆ = _______
C=
H=
Physics
2 answers:
Rzqust [24]3 years ago
8 0
H2SO4
H= 2
S=1
0=4

4KNO3
K=4
N=1
O=3
Oksanka [162]3 years ago
7 0

Answer:

Please mark as Brainliest!!

Explanation:

Explanation:

In a chemical formula, the symbols for each element in the compound are followed by subscripts that tell us how many of that element are in the compound.

For an example, let's look at the the formula for compound glucose:

C 6  H 12  O 6

________

The subscripts that follow each element's symbol indicate how many of that element are in the compound.

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Answer:

  • Corey's max speed is 7 \frac{m}{s}
  • the distance Corey's covers in z seconds is 7 \frac{m}{s} * z \ s
  • d (z) = 45 m + 7 \frac{m}{s} * z
  • d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

Explanation:

<h3>Corey's max speed</h3>

For constant speed, we know:

v=\frac{distance}{time}

The distance between the 80 meters and the 45 meters is:

distance = 80 m - 45 m = 35 m

and the time it took to reach the 80 meter will be:

time = 12 s - 7 s = 5 s

So, Corey's max speed is

v_{max}=\frac{35 m}{5 s} = 7 \frac{m}{s}

<h3>How far runs Corey</h3>

As the velocity of Corey's is v_{max}, the distance Corey's covers in z seconds is

distance = v_{max} * z \ s

distance = 7 \frac{m}{s} * z \ s

<h3>What is Corey's distance from the starting line</h3>

At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (z) = 45 m + v_{max} * z

d (z) = 45 m +7 \frac{m}{s} * z

At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (x) = 45 m + v_{max} * (x-7 s)

d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

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The launch velocity of the projectile is 13.28 m/s.

What is projectile motion?

The motion of an object thrown in the air under the force of gravity is known as projectile motion.

Since the object is launched horizontally, its initial velocity along the vertical direction is zero. From the second kinematic equation,

s=u*t+(1/2)at^2.

where s is the displacement, t is the time, u is the initial velocity and a is the acceleration. Since the height is decreasing, so it will be taken negative.

For the vertical motion, s=-19.3 m, a=-9.8 m/s^2 and u=0. Put the values in the above equation and solve it.

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Since the velocity along the horizontal direction is constant, the displacement along the horizontal direction is given by the formula,

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For the horizontal motion, X=26.3 m and t=1.98 s. Put the values in this equation and solve it.

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