Ec₁=mv₁²/2=450*26²/2=225*676=152100 J
Ec₂=mv₂²/2=450*30²/2=225*900=202500 J
ΔEc=Ec₂-Ec₁=202500-152100=50.4 kJ
170-68 = 102 meters to catch the antelope
from a) 1 stride = 7 meters in 0.28 seconds
102/7 = 14.57 strides x 0.28 = 4.08 seconds total
V=D/T = 102/4.08 = 25 meters/second
1m/s = 3.6 K/H
25 x 3.6 = 90 Kilometers/ hour
The average velocity is a vector magnitude we can find that its value is:
v = 3.63 10-2 m/ s
with a direction 74 to the South of the East
Giving parameters
- The tabulated displacements
- The time of the motion t = 300 s
To find
The velocity in a vector quantity that is defined as the change in displacement between time during the interval
v =
Where v is the veloicity, Δs and Δt are de positivo and time variation
To find the displacement let's use the Pythagoras' theorem
d =
We assume that the displacements to the right (east) and upwards (north) are positive
Δx = 17-14
Δx = 3 m
Δy = 12 -22.5
Δy = -10.5 m
The distance traveled is
d =
d = 10.9 m
The speed module is
v = 10.9 / 300
v = 3.63 10⁻² m / s
The direction of this velocity is given by the angle of this displacement can be found using trigonometry
tan θ =
θ = tan⁻¹
θ = tan⁻¹
θ = -74º
This angle is measured clockwise from the positive side of the x-axis.
Orea way to give this angle is
θ = 74 south of East
In conclusion the average speed is
v = 3.63 10-2 m / s
With a direction 74 to the South of the East
Learn more about average velocity here:
brainly.com/question/12322912
im probably wrong but probably increase because if they get closer the static/sparks to cause a reaction
Answer:
demand (an amount) as a price from someone for a service rendered or goods supplied.