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larisa86 [58]
4 years ago
7

What are two lines that intersect to form right angles called?

Mathematics
2 answers:
Anna35 [415]4 years ago
6 0
C, perpendicular. it’s shaped kinda like a cross
Svet_ta [14]4 years ago
3 0
C because it’s c trust me
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For the following graph, determine if the graph represents a polynomial function. If it is a polynomial function, then determine
tankabanditka [31]

Using function concepts, it is found that the correct option is given by:

a.Yes, this graph represents a polynomial. There are two turning points and the least degree possible is three.

<h3>What is the least degree possible of a polynomial?</h3>

Supposing a polynomial with n turning points, the least possible degree is of n + 1.

In this problem, the polynomial has 2 turning points, hence the least possible degree is of 3 and option a is correct.

More can be learned about functions at brainly.com/question/25537936

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2 years ago
A ticket to see your favorite baseball team costs $45.18. That price decreases by $0.23 for every game lost during the regular s
adell [148]

Answer:

The price after 33 loses would be 37.59

Step-by-step explanation:

8 0
3 years ago
Which new angle is created by extending one side of a triangle?
Naily [24]

The answer is C)an exterior angle

7 0
4 years ago
What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in
vovangra [49]
<h3>Given :</h3>
  • Distance = 175
  • Time 1 = 4 hours

\\  \\

<h3>To find:</h3>
  • Different between two speeds when distance is same.

\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

we know:-

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

So:-

\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

\\  \\

\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

4 0
3 years ago
Can someone please help me with this
REY [17]
Your answer is C. $1.48
3 0
3 years ago
Read 2 more answers
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