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Anton [14]
3 years ago
14

Some help please physics

Physics
2 answers:
salantis [7]3 years ago
3 0
My best guess is A  There is missing a time unit in the question.  I know that 4.4 *5 = 21 so that would be my best guess.
REY [17]3 years ago
3 0
The car's AVERAGE speed is (21/2)=10.5 m/s. (Zero at the beginning, 21 at the end.). In order to cover 50m at an average speed of 10.5 m/s, it takes (50/10.5)=4.76 seconds. It took 4.76 seconds to accelerate to 21 m/s^2, so the average acceleration is (21/4.76)=4.2 seconds. You probably had a formula in class that would take you to 4.4, but this is the way I think it through without a lot of formulas.
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A skateboarder shoots off a ramp with a velocity of 5.1 m/s, directed at an angle of 55° above the horizontal. The end of the ra
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Answer

given,

initial velocity of skateboard = 5.1 m/s

angle above the horizontal = 55°

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a) maximum height of projectile

  H = \dfrac{u^2sin^2 \theta}{2g}

  H = \dfrac{5.1^2\times sin^2 55^0}{2\times 9.81}

         H =  0.889 m

the maximum height of the skateboard above the ground

         = 1 + 0.889

         = 1.889 m

b) time to reach the height

   t = \dfrac{u\ sin\theta}{g}

   t = \dfrac{5.1\ sin55^0}{9.8}

          t = 0.426 s

horizontal distance = u cos θ × t

                                = 5.1 × cos 55° × 0.426

horizontal distance = 1.25 m

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