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Tpy6a [65]
3 years ago
8

a horizental force of 310n exerted on 2.0kg ball as it rotates ( at arm's length) uniformly in horizental circle of radius 0.0.9

0m calculate the speed of the ball ​
Physics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

v=11.8m/s

Explanation:

speed of the ball

Force=mass*centripetal acceleration

Centripetal acceleration= V2/r

F=M*V2/r

Data

F=310N

M=2.0kg

r=0.90m

v=?

310N=(2.0kg)*V2/0.90m

cross multiply

279Nm=(2.0kg)V2

V2= 279Nm/2.0kg

V2=139.5Nm/kg

apply square root both sides

√V2=√139.5

V=11.8m/s

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25m/s

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<em />

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3 years ago
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Sergeeva-Olga [200]

Answer:

0.8

Explanation:

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The potential of the smaller sphere will be:

V_S = \frac{kq}{r}

The potential of the larger sphere will be:

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Inputting R = 4r,

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Since V_S = V_L = V,

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The charge of the larger sphere is:

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