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Tpy6a [65]
3 years ago
8

a horizental force of 310n exerted on 2.0kg ball as it rotates ( at arm's length) uniformly in horizental circle of radius 0.0.9

0m calculate the speed of the ball ​
Physics
1 answer:
vazorg [7]3 years ago
3 0

Answer:

v=11.8m/s

Explanation:

speed of the ball

Force=mass*centripetal acceleration

Centripetal acceleration= V2/r

F=M*V2/r

Data

F=310N

M=2.0kg

r=0.90m

v=?

310N=(2.0kg)*V2/0.90m

cross multiply

279Nm=(2.0kg)V2

V2= 279Nm/2.0kg

V2=139.5Nm/kg

apply square root both sides

√V2=√139.5

V=11.8m/s

You might be interested in
8892 ml to grams then to mg ​
andrew11 [14]

Answer:

8892 ml = 8892 gm = 8892000 mg

1 ml = 1 gram

8892 ml = 8892 gram

1 gram or ml = 1000 milligram

8892 ml = 8892 × 1000 = 8892000 milligram

hope this helps

have a good day :)

Explanation:

remember: 1 kilogram = 1000 gram = 1000000 milligram.

Milliliter is expressed same as gram and liter is expressed same as kilogram.

1 meter = 100 cm, 1 kilometer = 1000 meter,

1 cm = 10 millimeter.

7 0
2 years ago
Read 2 more answers
Describe what a hydrogen bond is. 6th grade answer
r-ruslan [8.4K]

Answer:

<em>Hydrogen bond is the attractive force between the hydrogen attached electronegative atom </em>

Explanation:

8 0
3 years ago
What's an acrostic poem for climate each line has to be written in a full sentence?
Mrac [35]
Acrostic poem is a poem where the initials of the main word is given a respective sentence starting with that initial.
C- Can you see any changes happened in our surrounding?
L- Let me open your eyes and wake up to the reality.
I- Ignoring the unprecedented changes in our environment is worsening.
M- Making a move? Let's start it now.
A- Another day might not come.
T- Take this opportunity to show to world that we care.
E- Even to smallest thing that we can share.
3 0
3 years ago
It took a crew 9 h 36 min to row 8 km upstream and back again. If the rate of flow of the stream was 2 km/h, what was the rowing
babunello [35]

Answer:

3 km/h

Explanation:

Let's call the rowing speed in still water x, in km/h.

Rowing speed in upstream is: x - 2 km/h

Rowing speed in downstream is: x + 2 km/h

It took a crew 9 h 36 min ( = 9 3/5 = 48/5) to row 8 km upstream and back again. Therefore:

8/(x - 2) + 8/(x + 2) = 48/5      (notice that: time = distance/speed)

Multiplying by x² - 2², which is equivalent to (x-2)*(x+2)

8*(x+2) + 8*(x-2) =  (48/5)*(x² - 4)

Dividing  by 8

(x+2) + (x-2) = (6/5)*(x² - 4)

2*x = (6/5)*x² - 24/5

0 =  (6/5)*x² - 2*x - 24/5

Using quadratic formula

x = \frac{2 \pm \sqrt{(-2)^2 - 4(6/5)(-24/5)}}{2(6/5)}

x = \frac{2 \pm 5.2}{2.4}

x_1 = \frac{2 + 5.2}{2.4}

x_1 = 3

x_2 = \frac{2 - 5.2}{2.4}

x_2 = -1\; 1/3

A negative result has no sense, therefore the rowing speed in still water was 3 km/h

7 0
3 years ago
A hoodlum throws a stone vertically downward with an initial speed v0 from the roof of a building, a height h above the ground.
Vaselesa [24]
V2=u2+2as
v2=144+600
v2=744
v=√744
6 0
3 years ago
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