1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dusya [7]
3 years ago
8

If you are following a car and also being tailgated by another vehicle, your best option would be to.. a. Increase the following

distance between you and the car in front of you b. Slam on your breaks immediately c. Speed up to increase the space between you and the tailgating car d. Slowly and steadily apply your breaks
Physics
2 answers:
Pie3 years ago
7 0

Answer:

Your answer here is D

Explanation:

Slowly pressing your breaks will help ensure you are not hit by the other car. If they hit you its their fault. Hope this helps :)!

Rufina [12.5K]3 years ago
5 0

Answer:

<h2>D. Slowly and steadily apply your breaks.</h2>

Explanation:

When a person is being tailgated by another vehicle there's a risk of accident, due to the difference of speeds. When someone is being tailgated by another vehicle, it's because they vehicle doesn't work, cannot move by itself, so one vehicle impulse another.

To avoid any accident, the vehicle that's being tailgated must apply breaks often and slowly to try to maintain the same constant distance and speed than the other vehicle. This constant distance is what avoid accidents.

Therefore, the right answer is D.

You might be interested in
A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks
Alina [70]

Answer:

The position of the spring in terms of g, m & k is x = \frac{m g}{k}

Explanation:

Stiffness of the spring = k

Mass = m

When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.

⇒ Force exerted on the spring F = k x

⇒ m g = k x

⇒ x = \frac{m g}{k}

This is the position of the spring in terms of g, m & k.

8 0
4 years ago
The weight of a body of certain mass becomes zero in space.why?write with reasons​
Anvisha [2.4K]

Answer:

Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.

hope this helps u

Explanation:

7 0
3 years ago
Which force is greater the earth’s pull on the moon or the moon’s pull on the earth
Vitek1552 [10]

Answer:

The earth's pull on the moon

Explanation:

Earth exerts a gravitational pull on the moon 80 times stronger than the moon's pull on the Earth.

7 0
3 years ago
Cotton balls could be used to represent clouds because of their white color and appearance of texture. Which of these other thin
iris [78.8K]

I just did it the answer is..... B.cobwebs

:)

8 0
3 years ago
Read 2 more answers
In a 400-m relay race the anchorman (the person who runs the last 100 m) for team A can run 100 m in 9.8 s. His rival, the ancho
melisa1 [442]

Answer:

largest lead = 3 m

Explanation:

Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.

So, first we need to calculate the velocities of both the anchorman  

given data:

Distance = d = 100 m

Time arrival for A = 9.8 s

Time arrival for B = 10.1 s

Velocity of anchorman A = D / Time arrival for A

=100/ 9.8 = 10.2 m/s

Velocity of anchorman B = D / Time arrival for B

=100/10.1 = 9.9 m/s

As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use

d = vt

= 9.9 x 9.8 = 97 m  

So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.

largest lead = 100 - 97 = 3 m

So if his lead no more than 3 m anchorman A win the race.

5 0
3 years ago
Other questions:
  • The tape in a videotape cassette has a total
    14·1 answer
  • How long does it take electrons to get from the car battery to the starting motor? Assume the current is 143 A and the electrons
    13·1 answer
  • What never change despite what planet you go to
    14·1 answer
  • Which type of thermal energy transfer warms your hand when you hold it near a glass of hot water?
    7·1 answer
  • (WILL MARK BRAINLIEST and 27pts) What is the formula used to calculate the distance to an object in parsecs
    7·2 answers
  • A neutral atom can be negatively charged by
    15·1 answer
  • What is the reaction force to a foot pushing down on the floor?
    14·2 answers
  • Describe the frequency and wavelength range of radio waves
    14·1 answer
  • A push on a 1-kg brick accelerates it. Neglecting friction, equally accelerating a 10-kg brick requires 10 times as much force.
    11·1 answer
  • Which statement describes a surface wave?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!