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dusya [7]
3 years ago
8

If you are following a car and also being tailgated by another vehicle, your best option would be to.. a. Increase the following

distance between you and the car in front of you b. Slam on your breaks immediately c. Speed up to increase the space between you and the tailgating car d. Slowly and steadily apply your breaks
Physics
2 answers:
Pie3 years ago
7 0

Answer:

Your answer here is D

Explanation:

Slowly pressing your breaks will help ensure you are not hit by the other car. If they hit you its their fault. Hope this helps :)!

Rufina [12.5K]3 years ago
5 0

Answer:

<h2>D. Slowly and steadily apply your breaks.</h2>

Explanation:

When a person is being tailgated by another vehicle there's a risk of accident, due to the difference of speeds. When someone is being tailgated by another vehicle, it's because they vehicle doesn't work, cannot move by itself, so one vehicle impulse another.

To avoid any accident, the vehicle that's being tailgated must apply breaks often and slowly to try to maintain the same constant distance and speed than the other vehicle. This constant distance is what avoid accidents.

Therefore, the right answer is D.

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You could use an elevator or the stairs to lift a box to tenth floor.which has greater power?
erastova [34]

Stairs don't have any power at all.  All the energy used to climb them
has to come from your muscles.

An elevator gets its power from the electric motors that lift it.  All YOU
have to do is stand there and look around.

All of this is a big part of the reason why elevators have become so
popular, and why no buildings with more than a few floors were built
before elevators were invented.


7 0
3 years ago
1.- Un barco recorre la distancia que separa Gran Canaria de Tenerife (90 km) en 6 horas. ¿Cuál es
bezimeni [28]

Answer:

The speed is 15 km/h or 4.16 m/s.

Explanation:

A boat travels the distance that separates Gran Canaria from Tenerife (90 km) in 6 hours. Which  the speed of the boat in km / h? And in m / s?

Given that,

Distance, d = 90 km = 90000 m

Time, t = 6 hours = 21600 s

Speed = distance/time

v=\dfrac{90\ km}{6\ h}\\\\=15\ km/h

or

v=\dfrac{90000\ m}{21600\ s}\\\\=4.16\ m/s

So, the required speed is 15 km/h or 4.16 m/s.

7 0
3 years ago
Why does the amount of damage to a car depend on speed?
Zina [86]

if you are going slow, there wont be much of an effect or not any damage.

3 0
3 years ago
A 0.40 kg mass hangs on a spring with a spring constant of 12 N/m. The system oscillated with a constant amplitude of 12 cm. Wha
Vaselesa [24]

Answer:

The maximum acceleration of the system is 359.970 centimeters per square second.

Explanation:

The motion of the mass-spring system is represented by the following formula:

x(t) = A\cdot \cos (\omega \cdot t + \phi)

Where:

x(t) - Position of the mass with respect to the equilibrium position, measured in centimeters.

A - Amplitude of the mass-spring system, measured in centimeters.

\omega - Angular frequency, measured in radians per second.

t - Time, measured in seconds.

\phi - Phase, measured in radians.

The acceleration experimented by the mass is obtained by deriving the position equation twice:

a (t) = -\omega^{2}\cdot A \cdot \cos (\omega\cdot t + \phi)

Where the maximum acceleration of the system is represented by \omega^{2}\cdot A.

The natural frequency of the mass-spring system is:

\omega = \sqrt{\frac{k}{m} }

Where:

k - Spring constant, measured in newtons per meter.

m - Mass, measured in kilograms.

If k = 12\,\frac{N}{m} and m = 0.40\,kg, the natural frequency is:

\omega = \sqrt{\frac{12\,\frac{N}{m} }{0.40\,kg} }

\omega \approx 5.477\,\frac{rad}{s}

Lastly, the maximum acceleration of the system is:

a_{max} = \left(5.477\,\frac{rad}{s})^{2}\cdot (12\,cm)

a_{max} = 359.970\,\frac{cm}{s^{2}}

The maximum acceleration of the system is 359.970 centimeters per square second.

7 0
3 years ago
A 25 kg child stands 2.5 m from the center of a frictionless merry‐go‐round, which has a 200 kg*m^2 moment of inertia and is spi
vodka [1.7K]

Answer:

Explanation:

a ) Time period  T = 2 s

Angular velocity ω = 2π / T

=  2π / 2 = 3.14 rad /s

Initial moment of inertia I₁ = 200 + mr²

= 200 + 25 x 2.5²

=356.25

Final moment of inertia

I₂ = 200 + 25 X 1.5 X 1.5

= 256.25

b ) We apply law of conservation of momentum

I₁ X ω₁ =  I₂ X ω₂

ω₂ = I₁ X ω₁ / I₂

Putting the values

w_2=\frac{356.25\times3.14}{256.25}

ω₂ = 4.365 rad s⁻¹

c ) Increase in rotational kinetic energy

=1/2 I₂ X ω₂² -  1/2 I₁ X ω₁²

.5 X 256.25 X 4.365² - .5 X 356.25 X 3.14²

= 684.95 J

This energy comes from work done against the centripetal pseudo -force.

7 0
3 years ago
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