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dusya [7]
3 years ago
8

If you are following a car and also being tailgated by another vehicle, your best option would be to.. a. Increase the following

distance between you and the car in front of you b. Slam on your breaks immediately c. Speed up to increase the space between you and the tailgating car d. Slowly and steadily apply your breaks
Physics
2 answers:
Pie3 years ago
7 0

Answer:

Your answer here is D

Explanation:

Slowly pressing your breaks will help ensure you are not hit by the other car. If they hit you its their fault. Hope this helps :)!

Rufina [12.5K]3 years ago
5 0

Answer:

<h2>D. Slowly and steadily apply your breaks.</h2>

Explanation:

When a person is being tailgated by another vehicle there's a risk of accident, due to the difference of speeds. When someone is being tailgated by another vehicle, it's because they vehicle doesn't work, cannot move by itself, so one vehicle impulse another.

To avoid any accident, the vehicle that's being tailgated must apply breaks often and slowly to try to maintain the same constant distance and speed than the other vehicle. This constant distance is what avoid accidents.

Therefore, the right answer is D.

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What is Density? (3-5 sentences or your own word don't copy the<br> notes)
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Explanation:

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The smallest detail visible with ground-based solar telescopes is about 1 arc second. How large a region (in km) does this repre
mestny [16]

Answer:

x = 727.5 km

Explanation:

With the conditions given using trigonometry, we can find the tangent

       tan θ = CO / CA

With CO the opposite leg and CE is the adjacent leg which is the distance from the Tierral to Sun

   

        D =150 10⁶ km (1000m / 1 km)

        D = 150 10⁹ m.

We must take the given angle to radians.

       1º  = 3600 arc s  

       π rad = 180º

       θ = 1 arc s (1º / 3600 s arc) (pi rad / 180º) =

       θ = 4.85 10⁻⁶ rad

That angle is extremely small, so we can approximate the tangent to the angle

     

       θ = x / D

       x = θ D

       x = 4.85 10-6  150 109

       x = 727.5 103 m

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4 0
3 years ago
A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the
BARSIC [14]

Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

F_g=\frac{2.4012*10^{40}}{3.721*10^{23}} and now when I divide I will express my answer to the correct number of sig dig's:

Fg= 6.45 × 10¹⁶ N

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Are any rocks that form from another rock as a result of change in blank or blank
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The correct answer is rock cycle
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