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MrRissso [65]
3 years ago
8

What is the equivalent resistance if you connect three 10.0 Ω resistors in series?

Physics
2 answers:
Sonja [21]3 years ago
4 0

Req = 30.0Ω.

When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.

Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω

denpristay [2]3 years ago
4 0

Answer:

Req = 30.0Ω.

Explanation:

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Answer:

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In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.

\frac{N_{p} }{N_{s} } =\frac{V_{p} }{V_{s} }\\

Using the given values, we get:

\frac{100}{200}=\frac{1.5}{V_{s} }\\V_{s}=1.5 \times \frac{200}{100}\\V_{s}=3

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