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MrRissso [65]
3 years ago
8

What is the equivalent resistance if you connect three 10.0 Ω resistors in series?

Physics
2 answers:
Sonja [21]3 years ago
4 0

Req = 30.0Ω.

When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.

Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω

denpristay [2]3 years ago
4 0

Answer:

Req = 30.0Ω.

Explanation:

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Imagine that the Earth had no atmosphere and was covered with a material that was a perfect thermal insulator (and zero thermal
Butoxors [25]

Answer:

T_{12 \ pm} = 360 \ K

T_{3 \ pm} = 330 \ K

T = 131\ K

Explanation:

The power of sunlight at equator L_{sun} is known to be = 3.846*10^{26} \ W

Distance = 1 Au = 1.496*10^{11} \ m

Thus; the power at equator = \frac{3.846*10^{26}}{4 \pi *(1.496*10^{11})^2}

= 1367 W/m²

Now; at noon (sun overhead)

1367* \frac{70}{100}= 5.67*20^{-8}*T^4\\\\T^4 =\frac{956.9}{5.67*10^{-8}}\\\\T^4 = 1.687*10^{10}\\\\T_{12 \ pm} = 360 \ K

At 3 pm (Sun 45 degrees from overhead);

1367* \frac{70}{100}*cos \ 45 = 5.67*20^{-8}*T^4\\\\T^4 =\frac{676.63}{5.67*10^{-8}}\\\\T^4 = 1.193*10^{10}\\\\T_{3 \ pm} = 330 \ K

C) sunset and D) midnight.

We based our assumption on the notion that the incident angle at sunset and midnight be just below 90° ; for example . let say:

T_{6pm \  to \ 6 am} =  1367* \frac{70}{100}*cos 89 = \sigma T^4\\ \\T = 131\ K

5 0
3 years ago
A gold bar contains 63.0 mol of gold, Au(s). How many atoms of gold are in the bar?
vredina [299]

Answer:

63.0 x (6.02 x 10^23) = 3.79 x 10^25 atoms of gold

Explanation:

There are 6.02 x 10^23 representative particles in a mole of any substance. Multiply it by the number of moles, and you will get the number of representative particles (atoms, molecules, formula units)

7 0
3 years ago
5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there
Jobisdone [24]

Answer:

the fractional loss per pass =0.053

the decay time of the cavity =11 ns

Explanation:

laser is an acronym for Light Amplification by Stimulated Emission of Radiation and it has lot of military applications : basically ranging from target acquisition, fire control, and training. It is also being used  in LIDAR communications, radar systems , laser guided landing systems, laser pointers, holography, photography, guidance systems, scanning machines, metal working,  and medicine.

the fractional loss per pass= \alpha l - ln(R_1R_2)^ \frac {1}{2}

but no excited state absorption, therefore \alpha is 0

= - ln(R_1R_2)^ \frac {1}{2}\\\\=- ln(0.999* 0.9)^ \frac {1}{2}

=0.053

b) the decay time of the cavity:

T_c = \frac{nd}{cl_f}=\frac{1,76 * 10 *10^-2}{3 *10^8 *0.53}

=1.1 *10^-8 seconds

=11 ns

3 0
3 years ago
Three point charges are placed at distances of d , 2 d , and 3 d from a point P. The particle that is 2 d away from P has a char
mel-nik [20]

Answer:

at d the charge will be 3q and at 3d it will be 9q

Explanation:

for V=Vp-V2d

V=KQ/d=K*6q/2d=3kq/d for potential to 2d at 6q be zero the Vp will equal 3kq/d; hence at d, Q=3q and at 3d, Q=9q

7 0
3 years ago
Which statement best describes what Kendall can measure?
Vaselesa [24]

Answer + Explanation:

B

She can measure the volume and mass of the marble, the volume and mass of the water, and the mass of the graduated cylinder.




Hope This Helped :D

6 0
2 years ago
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