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4 years ago

What is the equivalent resistance if you connect three 10.0 Ω resistors in series?

Physics

2 answers:

Sonja [21]4 years ago

4 0

Req = 30.0Ω.

When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.

Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω

denpristay [2]4 years ago

4 0

Answer:

Req = 30.0Ω.

Explanation:

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3 years ago

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Answer:

Option:(D)-

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3 years ago

Find the values of the root mean square translational speed v, molecules in gaseous diatomic oxygen (O2), gaseous carbon dioxide

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Answer:

For diatomic oxygen:V=539.06 m/s

For carbon dia oxide:V=459.71 m/s

For dia atomic hydrogen:V=2156.25 m/s

Explanation:

As we know that

Root mean square velocity V

$V=\sqrt{\dfrac{3RT}{M}}$

Where

R is the gas constant

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

T is the temperature (K).

M is the molecular weight.

For diatomic oxygen:

M=32 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{32\times 10^{-3}}}$

V=539.06 m/s

For carbon dia oxide

M=44 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{44\times 10^{-3}}}$

V=459.71 m/s

For dia atomic hydrogen:

M= 2 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

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4 years ago

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Answer:

100% cold working performed on this steel

Explanation:

Using the constant volume assumption:

L₀W₀t₀ (initial) = Lₐ Wₐ tₐ (final)

thus 300 cm long X 80 cm wide X 8 cm thick = Lₐ x 80 cm wide X 5 cm thick

Lₐ = 300 cm long X 80 cm wide X 8 cm thick/80 cm wide X 5 cm thick

=480 cm

% cold working performed on this steel = Lₐ Wₐ tₐ (final) / L₀W₀t₀ (initial) 8 100

= 480 x 80 x 5/ 300 x 80 x 8 *100 = 100%

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3 years ago