Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Answer:
m - 10
Step-by-step explanation:
7 plus = 7 +
The sum of m and -17 = m + (-17)
7 + (m + -17)
We can get rid of the parentheses
7 + m + -17
Combine like terms
7 + -17 = -10
m + -10
Get rid of the addition sign
m - 10
To find the answer, you have to do 2/3 divided 4, which equals 2/12, which is the same as 1/6. You get the answer 1/6, because 2/3 divided 4 is the same as 2/3 times 1/4, and if you do the math, you get 2/12, and you simplify it to 1/6.
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