What will be the gravitational force of two bodies when distance between them is doubled

If something is traveling at 20 m/s constant velocity, is it in equilibrium? If a projectile is launched at a velocity of 20 m/s

Irina18 [472]

If something is traveling at 20 m/s constant speed AND its direction isn't changing, then its velocity is constant. Another way to say that is: Its acceleration is zero. Zero acceleration means zero NET force acting on the object, or a group of BALANCED forces acting on it, also called EQUILIBRIUM. The required answer is: YES.

If a real projectile is launched, the force of gravity acts on it vertically downward. There's no upward force acting on it to balance gravity. Therefore, the forces on the projectile are NOT balanced, there IS a net vertical force on it, and it's NOT in equilibrium. Too bad.

3 0

3 years ago

What is the velocity of the object?

dmitriy555 [2]

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2 /><h2> $\huge\boxed{\text{V = 9.5 m/s}}$ </h2><h2>_____________________________________</h2>

mass = m = 2kg

Distance = x = 6m

Force = 30N

TO FIND:

Work = W = ?

Velocity = V = ?

<h2>SOLUTION:</h2>

According to the object of mass 2 kg travels a distance when the force was exerted on it. The graph between the Force and position was plotted which shows that 30 N of force was used to push the object till the distance of 6.0m.

To find the work, I will use the method of determining the area of the plotted graph. As the graph is plotted in the straight line between the Force and work, THE PICTURE ATTCHED SHOWS THE AREA COVERED IN BLUE AS WORK DONE AND HEIGHT AS 30m AND DISTANCE COVERED AS 6m To solve for the area(work) of triangle is given as,

${\Longrightarrow}\qquad \qquad \qquad W\ =\ \frac{1}{2}\;(Base)\:(Height)$

Base is the x-axis of the graph which is Position i.e. 6m

Height is the y-axis of the graph which is Force i.e. 30N

So,

$W\ =\ \frac{1}{2}\:6\:x\:30$

W = 90 J

The work done is 90 J.

According to the principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

${\Longrightarrow}\qquad \qquad \qquad W\quad =\quad K.E\\\\{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad \frac{1}{2}\ m\ V^2 \\\\{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad \frac{1}{2}\ 2\ (V_f-V_i)^2\\\\{V_i\ is\ 0\ because\ the\ object\ was\ initially\ at\ rest}\\\\ {\Longrightarrow}\qquad \qquad \qquad W\quad\ =\ \frac{1}{2}\ x\ 2\ (V_f-0)^2 \\\\{\Longrightarrow}\qquad \qquad \qquad 90\quad = \frac{1}{2}\ x\ 2\ (V_f)^2$

$\\\\{\Longrightarrow}\qquad \qquad \qquad V_f\quad =\ \sqrt{\frac{2\ (90)\ }{2}}\\\\{\Longrightarrow}\qquad \qquad \qquad \boxed {V_f\quad =\ 9.48\ m/s}$

$\boxed{The\ Velocity\ of\ the\ Object\ of\ mass\ 2kg\ at\ 6\ meters\ of\ distance\ was\ 9.48\ m/s}$

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

8 0

3 years ago

How are traits influenced by the environment?

MAXImum [283]

Answer:

i dont k

Explanation:

7 0

3 years ago

Deduce a value for the latent heat of evaporation Lv of water. State clearly any simplifying assumptions that you make. Estimate

Stolb23 [73]

Find the below attachment

5 0

3 years ago

Read 2 more answers

You want to get a Q-taco from stripes so you head 3 miles at 45 degrees S of E. What

Cloud [144]

Trigonometry allows finding the result for the decomposition of the displacement vector is:

x = 2.12 mi

y = -2.12 mi

Displacement is a vector quantity, which has modulus and direction.

The cardinal points are a reference system with respect to which measurements are made, this system is related to the Cartesian system with the East in the positive direction of the x-axis and the North with the positive direction of the y-axis.

In the attached we can see a diagram of the vector and its components, the indicated direction of 45 S of the E, in the Cartesian system where the angles are measured from the positive side of the x-axis in a counterclockwise direction is:

θ = 360 - 45

θ = 315º

Let's use trigonometry to decompose the vector d = 3 mi

cos 315 = $\frac{x}{d}$

sin 315 = $\frac{y}{d}$

x = d cos 315

y = d sin 315

Let's calculate

x = 3 cos 315

y = 3 sin 315

x = 2.12 mi

y = -2.12 mi

The negative sign indicates that the displacement is towards the negative side, that is, towards the South.

In conclusion using trigonometry we can find the result for the decomposition of the displacement vector are:

x = 2.12 mi

y = -2.12 mi

Learn more here: brainly.com/question/1666179

3 0

3 years ago

What will be the gravitational force of two bodies when distance between them is doubled​

What will be the gravitational force of two bodies when distance between them is doubled