1) Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as
1 answer:
Explanation:
The tangential speed of Andrea is given by :
Where
r is radius of the circular path
ω is angular speed
The merry-go-round is rotating at a constant angular speed. Let the new distance from the center of the circular platform is r'
r' = 2r
New angular speed,
New angular speed is twice that of the Chuck's speed.
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Answer: To determine acceleration ,Micah also needs the Time of the total trip in seconds.
Explanation:
Acceleration can be defined as rate of change of velocity.
for calculating acceleration, initial and final velocity are required in meter per second and the total time of the trip in seconds. Then acceleration is measured in meter per second square.
Thus, Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the <u>Time</u> of the total trip in seconds.
Answer:
λ = 6.802 10⁻⁷ m, wavelength corresponds to orange almost red
Explanation:
The expression for constructive interference is
d sin θ = m λ
let's use trigonometry
tan θ = y / L
tan θ = sin θ / cos θ
interference experiments angles are very small
tan θ = sin θ = y / L
substituting
= m λ
in this case they indicate the separation of the slits d = 7.16 10-5 m, the order of the interference is m = 4, the distance y = 3.8 10-2 m and the separation to the screen L = 1 m
A) they ask us for the wavelength
λ =
let's calculate
λ = 7.16 10⁻⁵ 3.8 10⁻² /(4 1)
λ = 6.802 10⁻⁷ m
B) Let's reduce the wavelength to nm
λ = 6.802 10⁻⁷ m (109 nm / 1m)
λ = 680.2 nm
this wavelength corresponds to orange almost red