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ryzh [129]
3 years ago
7

A straight 1.0 m long wire is carrying a current. the wire is placed perpendicular to a magnetic field of strength 0.20 t. if th

e wire experiences a force of 0.60 n, what is the current in the wire?
Physics
1 answer:
Annette [7]3 years ago
5 0
A current carrying wire placed perpendicular to a magnetic field experiences a force equal to
F=ILB
where
I is the current in the wire
L is the wire length
B is the intensity of the magnetic field

In our problem, the length of the wire is L=1.0 m, the magnetic field strength is B=0.20 T and the force exerted on the wire is F=0.60 N. If we re-arrange the equation and we plug these numbers into it, we find the current in the wire:
I= \frac{F}{LB}= \frac{0.60 N}{(1.0 m)(0.20 T)}=3 A
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Answer:

Option D

a new invention lowers the cost of production

Explanation:

When there is a new invention lowers the cost of production, the production is likely to increase since the time allocated is as previous. Therefore, the curve moves to the right, to indicate a positive direction

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A dump truck and a little toy matchbox car have the same velocity. which one has the greater momentum?
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what are the common elements that make up series and parallel circuits , and how are circuits diagrammed?​
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<h2>Answer:</h2>

A series circuit occurs when the elements are connected along a simple path so the same current flows through all the elements. On the other hand, a parallel circuit occurs when there are two or more paths for the electricity to flow. The diagram are shown in the Figure below. We have chosen a source and resistors to illustrate this problem.

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A white dwarf star has a density of about 1.0 x 10^9 kg/m3. If the earth were to suddenly become as dense as a white dwarf star,
GalinKa [24]

Answer:

R = 98304.75 m = 98.3 km

Explanation:

The density of an object is given as the ratio between the mass of that object and the volume occupied by that object.

Density = Mass/Volume

Now, it is given that the density of Earth has become:

Density = 1 x 10⁹ kg/m³

Mass = Mass of Earth (Constant) = 5.97 x 10²⁴ kg

Volume = 4/3πR³ (Volume of Sphere)

R = Radius of Earth = ?

Therefore,

1 x 10⁹ kg/m³ = (5.97 x 10²⁴ kg)/[4/3πR³]

4/3πR³ = (5.97 x 10²⁴ kg)/(1 x 10⁹ kg/m³)

R³ = (3/4)(5.97 x 10¹⁵ m³)/π

R = ∛[0.95 x 10¹⁵ m³]

<u>R = 98304.75 m = 98.3 km</u>

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3 years ago
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