Answer:
a.) I = 7.8 × 10^-4 A
b.) V(20) = 9.3 × 10^-43 V
Explanation:
Given that the
R1 = 20 kΩ,
R2 = 12 kΩ,
C = 10 µ F, and
ε = 25 V.
R1 and R2 are in series with each other.
Let us first find the equivalent resistance R
R = R1 + R2
R = 20 + 12 = 32 kΩ
At t = 0, V = 25v
From ohms law, V = IR
Make current I the subject of formula
I = V/R
I = 25/32 × 10^3
I = 7.8 × 10^-4 A
b.) The voltage across R1 after a long time can be achieved by using the formula
V(t) = Voe^- (t/RC)
V(t) = 25e^- t/20000 × 10×10^-6
V(t) = 25e^- t/0.2
After a very long time. Let assume t = 20s. Then
V(20) = 25e^- 20/0.2
V(20) = 25e^-100
V(20) = 25 × 3.72 × 10^-44
V(20) = 9.3 × 10^-43 V
Answer:
Explanation:
In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.
For the step by step solution to the question you asked, go through the attached documents.
Answer:
The force that must be applied to maintain the vane speed constant is 2771.26 N
Explanation:
Given;
turning angle of the vane = 120°
control volume velocity, u = 10 m/s
absolute velocity, v = 30 m/s
nozzle area = 0.004 m²
The force acting on the vane has horizontal and vertical components:
Based on Reynolds general control volume system;
The horizontal force component of the system, ∑Fₓ = ρW²A(1-cosθ)
where;
ρ is the density of water = 1000 kg/m³
W is the relative velocity = Absolute velocity - control volume velocity
W = v - u
= 30 - 10 = 20m/s
∑Fₓ = ρW²A(1-cosθ) = 1000 x 20² x 0.004 (1 - cos 120) = 2400 N
The vertical force component of the system, ∑Fy = ρW²A(sinθ)
∑Fy = ρW²A(sinθ) = 1000 x 20² x 0.004 x sin(120) = 1385.6 N
The magnitude of the force applied
The force that must be applied to maintain the vane speed constant is 2771.26 N