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3 years ago

What does the current in a semi-conductor is produced by?

2 answers:

6 0

Current flow in a semiconductor arises from the motion of charge carriers in both the conduction and valence bands. As explained in chapter 4, the mobile charges in the conduction band are electrons and those in the valence band are holes.

lesya [120]3 years ago

5 0

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PLZ ANSWER SOON!!!

slava [35]

Answer:

You're answer would be "D. Perform all of the above"

Explanation:

Have a Blessed Day (Mark Brainliest!)

4 0

3 years ago

Read 2 more answers

What is a jack plane used for

kolezko [41]

A jack plane is a general purpose woodworking bench plane, used for dressing timber down to the correct size in preparation for truing and/or edge jointing.

I hope this helps you :)

4 0

3 years ago

A ten-station transfer machine has an ideal cycle time of 30 sec. The frequency of line stops is 0.075 stops per cycle. When a l

goldfiish [28.3K]

Answer:

62.5%

Explanation:

We are given that

A ten-station transfer machine has ideal cycle time=30 sec= $\frac{30}{60}=0.5 min$

Frequency of line=0.075 stops per cycle

Average time=4 min

We have to determine the line efficiency

$T_p=0.5+0.075(4)=0.5+0.3=0.8$

Line efficiency= $\frac{0.5}{0.8}\times 100=$ 62.5%

Hence, the line efficiency=62.5%

8 0

4 years ago

The current drawn by fluorescent lighting has a high total harmonic distortion. For this case, THD is calculated to be 88%. The

Alona [7]

Answer:

displacement power factor is 0.959087

Explanation:

given data

THD = 88%

true power factor = 0.72

solution

we get here total harmonic distribution THD is express as here

THD = $\sqrt{\frac{1}{g^2}-1}$ ..............1

her g is distortion factor

so put here value and we will get g that is

0.88² = $\frac{1}{g^2} -1$

solve it we get

g = 0.750714

and

displacement power factor is express as

DPF = $\frac{PF}{g}$ .................2

put here value and we will get

DPF = $\frac{0.72}{0.750714}$

DPF = 0.959087

3 0

3 years ago

Steam enters a turbine operating at steady state at 2 MPa, 323 °C with a velocity of 65 m/s. Saturated vapor exits at 0.1 MPa an

Lera25 [3.4K]

Answer:

$\dot Q_{out} = 13369.104\,kW$

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

$-\dot Q_{out} - \dot W_{out} + \dot H_{in} - \dot H_{out} + \dot K_{in} - \dot K_{out} + \dot U_{in} - \dot U_{out} = 0$

The rate of heat transfer between the turbine and its surroundings is:

$\dot Q_{out} = \dot H_{in}-\dot H_{out} + \dot K_{in} - \dot K_{out} - \dot W_{out} + \dot U_{in} - \dot U_{out}$

The specific enthalpies at inlet and outlet are, respectively:

$h_{in} = 3076.41\,\frac{kJ}{kg}$

$h_{out} = 2675.0\,\frac{kJ}{kg}$

The required output is:

$\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW$ $\dot Q_{out} = 13369.104\,kW$

4 0

3 years ago