Answer:
Make a PBJ
Explanation:
First you remove the bread from the fridge, cabinet, ect.
Then you remove 2 slices from the packaging and place them on a clean spot on the counter, a paper towel, or a plate. (You can put them in the toaster if you prefer toasted bread)
Retreive the peanut butter and jelly from their respective places, and bring them to the area with your bread. If you are toasting the bread, wait til the toaster is done, then place your slices back on your surface.
Now, take a butter knife and spread peanut butter on one side of a peice of bread. Make sure the edges are covered for the best result.
Do the same with the Jelly.
Now put both peices of bread together, the Peanut butter and jelly facing each other. Finally enjoy your sandwich!
The reason for this is that in almost all ionic compounds, there is an equivalent transfer and acceptance of the same number of electrons, whereby each transfer results in a + and receiver is a -. This ultimately cancels out when the ions come close together.
For a polar molecule<span>, your bonds will not cancel out. This means that in a </span>polar<span> bond, the electronegativity of the atoms will be different. For </span>nonpolar<span> bonds the electronegativity of the atoms will be equal. In a </span>polar<span> bond you will have an unequal sharing of electron pairs which causes a molecular dipole.</span>
Answer: B. (A 25 kg ball)
Explanation:
Since
, and velocity is the same for all four balls, the ball with the greatest mass will have the greatest kinetic energy (since mass and KE are directly related). Below shows these calculations:
A. m = 5
![KE = \frac{1}{2} mv^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20%5C%5C)
![KE = \frac{1}{2} (5)v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%285%29v%5E%7B2%7D%20%5C%5C)
![KE = 2.5v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%202.5v%5E%7B2%7D%20%5C%5C)
B. m = 25
![KE = \frac{1}{2} mv^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20%5C%5C)
![KE = \frac{1}{2} (25)v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2825%29v%5E%7B2%7D%20%5C%5C)
![KE = 12.5v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%2012.5v%5E%7B2%7D%20%5C%5C)
C. m = 10
![KE = \frac{1}{2} mv^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20%5C%5C)
![KE = \frac{1}{2} (10)v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2810%29v%5E%7B2%7D%20%5C%5C)
![KE = 5v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%205v%5E%7B2%7D%20%5C%5C)
D. m = 1
![KE = \frac{1}{2} mv^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20%5C%5C)
![KE = \frac{1}{2} (1)v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281%29v%5E%7B2%7D%20%5C%5C)
![KE = 0.5v^{2} \\](https://tex.z-dn.net/?f=KE%20%3D%200.5v%5E%7B2%7D%20%5C%5C)