D. oxygen is used to break down glucose into energy
Explanation:
During respiration, oxygen is used to break down glucose into energy:
C₆H₁₂O₆ + O₂ → CO₂ + H₂O + energy
In the process of respiration, oxygen gas combines with glucose to liberate energy.
- Respiratory system in the body is responsible for the metabolic break down of food to provide energy for the working of the human body.
- Chemical energy in glucose is broken down to produce other forms of energy most especially heat.
- The by product is usually carbon dioxide and water vapor.
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Answer:
4.75 moles of Fe
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
FeO + CO —> Fe + CO2
Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:
From the balanced equation above,
1 mole of FeO reacted to produce 1 mole of Fe.
Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.
Therefore, 4.75 moles of Fe is produced.
Answer:
ΔH of the reaction is -802.3kJ.
Explanation:
Using Hess's law, you can know ΔH of reaction by the sum of ΔH's of half-reactions.
Using the reactions:
<em>(1) </em>Cgraphite(s)+ 2H₂(g) → CH₄(g) ΔH₁ = −74.80kJ
<em>(2) </em>Cgraphite(s)+ O₂(g) → CO₂(g) ΔH₂ = −393.5k
J
<em>(3) </em>H₂(g) + 1/2 O₂(g) → H₂O(g) ΔH₃ = −241.80kJ
The sum of (2) - (1) produce:
CH₄(g) + O₂(g) → CO₂(g) + 2H₂(g) ΔH' = -393.5kJ - (-74.80kJ) = -318.7kJ
And the sum of this reaction with 2×(3) produce:
CH₄(g) + 2 O₂(g) → CO₂(g) + 2H₂O(g) And ΔH = -318.7kJ + 2×(-241.80kJ) =
<em>-802.3kJ</em>
Answer: Option (A) is the correct answer.
Explanation:
Force acting on a dam is as follows.
F = 
.......... (1)
Now, when we double the depth then it means H is increasing 2 times and then the above relation will be as follows.
F' = 
F' = 
........... (2)
Now, dividing equation (1) by equation (2) as follows.
= 
Cancelling the common terms we get the following.
= 
4F = F'
Thus, we can conclude that if doubled the depth of the dam the hydrostatic force will be 4F.
