Answer:
10 m/s
Explanation:
= Mass of arrow = 1 kg
= Mass of apple = 2 kg
= Initial Velocity of arrow = 30 m/s
= Initial Velocity of apple = 0 m/s
= Velocity of combined mass
For elastic collision
![m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1\times 30 + 2\times 0}{1 + 2}\\\Rightarrow v=10\ m/s](https://tex.z-dn.net/?f=m_1u_1%20%2B%20m_2u_2%20%3D%28m_1%20%2B%20m_2%29v%5C%5C%5CRightarrow%20v%3D%5Cfrac%7Bm_1u_1%20%2B%20m_2u_2%7D%7Bm_1%20%2B%20m_2%7D%5C%5C%5CRightarrow%20%20v%3D%5Cfrac%7B1%5Ctimes%2030%20%2B%202%5Ctimes%200%7D%7B1%20%2B%202%7D%5C%5C%5CRightarrow%20v%3D10%5C%20m%2Fs)
Final velocity of apple and arrow after collision is 10 m/s
Displacement can be zero so velocity is zero but the distance won’t be zero so speed won’t be zero
Answer:
the speed of the command module relative to Earth just after the separation = 4943.2 Km/hr
Explanation:
Given:
speed of space vehicle =5000 km/hr
rocket motor speed = 71 km/hr relative to the command module
mass of module = m
mass of motor = 4m
By conservation of linear momentum
Pi = Pf
Pi= initial momentum
Pf= final momentum
Since, the motion is only in single direction
![MV_i=4mV_{mE}+mV_{cE}](https://tex.z-dn.net/?f=MV_i%3D4mV_%7BmE%7D%2BmV_%7BcE%7D)
Where M is the mass of the space vehicle which equals the sum of motor's mass and the command's mass, Vi its initial velocity, V_mE is velocity of motor relative to Earth, and V_cE is its velocity of the command relative to Earth.
The velocity of motor relative to Earth equals the velocity of motor relative to command plus the velocity of command relative to Earth.
V_mE = V_mc+V_cE
Where V_mc is the velocity of motor relative to command this yields
![5mV_i = 4m(V_{mc}+V_{cE})+mV_{cE}](https://tex.z-dn.net/?f=5mV_i%20%3D%204m%28V_%7Bmc%7D%2BV_%7BcE%7D%29%2BmV_%7BcE%7D)
![5V_i = 4V_{mc}+5V_{cE}](https://tex.z-dn.net/?f=5V_i%20%3D%204V_%7Bmc%7D%2B5V_%7BcE%7D)
substituting the values we get
![V_{cE} = \frac{5V_i-4V_{mc}}{5}](https://tex.z-dn.net/?f=V_%7BcE%7D%20%3D%20%5Cfrac%7B5V_i-4V_%7Bmc%7D%7D%7B5%7D)
![V_{cE} = \frac{5(5000)-4(71)}{5}](https://tex.z-dn.net/?f=V_%7BcE%7D%20%3D%20%5Cfrac%7B5%285000%29-4%2871%29%7D%7B5%7D)
= 4943.2 Km/hr
the speed of the command module relative to Earth just after the separation = 4943.2 Km/hr
The phenomenon that best illustrates on matter behaving like a wave instead of being a particle is called the interference patterns of electrons. In addition, this phenomenon was described by experimenting that made use of an electron wherein the wave nature of electrons was observed.