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Anna35 [415]
3 years ago
14

An Arrow (1 kg) travels with velocity 30 m/s to the right when it pierces an apple (2 kg) which is initially at rest. After the

collision, the arrow and the apple are stuck together. Assume that no external forces are present and therefore the momentum for the system is conserved. What is the final velocity (in m/s) of apple and arrow after the collision?
Physics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

10 m/s

Explanation:

m_1 = Mass of arrow = 1 kg

m_2 = Mass of apple = 2 kg

u_1 = Initial Velocity of arrow = 30 m/s

u_2 = Initial Velocity of apple = 0 m/s

v = Velocity of combined mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow  v=\frac{1\times 30 + 2\times 0}{1 + 2}\\\Rightarrow v=10\ m/s

Final velocity of apple and arrow after collision is 10 m/s

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Answer:

5.731\times 10^{-5}\ m/s

Decrease

Explanation:

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e = Charge of electron = 1.6\times 10^{-19}\ C

n = Conduction electron density in copper = 8.49\times 10^{28}\ electrons/m^3

v_d = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s

The drift speed of the electrons is 5.731\times 10^{-5}\ m/s

v_d=\dfrac{I}{neA}

From the equation we can see the following

v_d\propto \dfrac{1}{n}

So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.

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The mass of a star is 1.61·1031 kg and its angular velocity is 1.60E-7 rad/s. Find its new angular velocity if the diameter sudd
Tcecarenko [31]

Answer:

ω₂ = 1.9025 x 10⁻⁶ rad/s

Explanation:

given,

mass of star = 1.61 x 10³¹ kg

angular velocity = 1.60 x 10⁻⁷ rad/s

diameter suddenly shrinks = 0.29 x present size

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using conservation of angular momentum

I₁ ω₁ = I₂ ω₂

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\omega_2=\dfrac{1.60\times 10^{-7}}{0.0841}

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