Answer:
P = d g h pressure due to density of liquid of height h
d1 g h1 = d2 g h2 since P1 equals P2
d1 h1 = d2 h2 and the density of Hg is 13.6 times that of water
h2 = (d1 / d2) * h1 = 13.6 * 70 cm = 952 cm or 9.52 m
Answer:
The First is an example of acceleration, the second is an example of velocity
The electric field strength is inversely related to the square of the distance.so the strength of the electric field is given by
Here, 
is constant depend upon medium and its value is 
and q is charge and r is the distance.
Given 
and we know the charge of proton, 
.
Therefore,
Answer:
The minimum distance between two points on the object that are barely resolved is 0.26 mm
The corresponding distance between the image points = 0.0015 m
Explanation:
Given
focal length f = 50 mm and maximum aperture f>2
s = 9.0 m
aperture = 25 mm = 25 *10^-3 m
Sin a = 1.22 *wavelength /D
Substituting the given values, we get –
Sin a = 1.22 *600 *10^-9 m /25 *10^-3 m
Sin a = 2.93 * 10 ^-5 rad
Now
Y/9.0 m = 2.93 * 10 ^-5
Y = 2.64 *10^-4 m = 0.26 mm
Y’/50 *10^-3 = 2.93 * 10 ^-5
Y’ = 0.0015 m
<span>a.The hiker had an easy, level trail from 11:00-12:00 and was able to travel the fastest during that time period.---> may be because this was indeed fastest stage
b.The hiker got tired and walked the slowest from 1:00-2:00.---> no, because this was not the slowest stage
c.The hiker stopped for lunch from 11:00-12:00 and that slowed him down.---> no because this was the fastest stage
d.The hiker ended up in the same place that he started.---> no, because the hiker walked more toward east than toward west and more toward south than toward north.
Answer: option a) </span>
